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CaHeK987 [17]
3 years ago
8

A solution of pyridinium bromide has a pH of 3.00. What is the concentration of the pyridinium cation at equilibrium, in units o

f molarity? Express molarity to two decimal places.
Chemistry
1 answer:
Artemon [7]3 years ago
4 0

Answer:

The concentration of the pyridinium cation at equilibrium is 1.00×10⁻³ M

Explanation:

In water we have

C₅H₅NHBr + H₂O ⇒ C₅H₅NH+ + Br−

Pyridinium Bromide (C₅H₅NHBr) Dissociates Completely  Into C₅H₅NH+ And Br− as such it is a strong Electrolyte.

Therefore the number of moles of positive ion produced per mole of C₅H₅NHBr  is one

pH = - log [H₃O⁺] Therefore 10^-pH = [H₃O⁺] = concentration of C₅H₅NHBr

= 10⁻³ = 0.001M = concentration of C₅H₅NHBr

The concentration of C₅H₅NHBr is = 1.00×10⁻³ M to two places of decimal

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The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc
jek_recluse [69]

Answer: K_{sp}=1.25\times 10^{-14}

pK_{sp}=13.90

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}  

The equation for the ionization of magnesium phosphate is given as:

Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}

 When the solubility of Mg_3(PO_4)_2 is S moles/liter, then the solubility of Mg^{2+} will be 3S moles\liter and solubility of PO_4^{3-} will be 2S moles/liter.

Thus S = 0.173 g/L or \frac{0.173g/L}{262.8g/mol}=0.00065mol/L

K_{sp}=(3S)^3\times (2S)^2

K_{sp}=108S^5

K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}

pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90

5 0
3 years ago
What is the relationship between gravity and water
Leni [432]
Water Is A Liquid And Gravity Pulls Objects Up
7 0
3 years ago
Given that the freezing point depression constant for water is 1.86°c kg/mol, calculate the change in freezing point for a 0.907
melamori03 [73]

Answer : The correct answer for change in freezing point = 1.69 ° C

Freezing point depression :

It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .

SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .

It can be expressed as :

ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m

Where : ΔTf = change in freezing point (°C)

i = Von't Hoff factor

kf =molal freezing point depression constant of solvent.\frac{^0 C}{m}

m = molality of solute (m or \frac{mol}{Kg} )

Given : kf = 1.86 \frac{^0 C*Kg}{mol}

m = 0.907 \frac{mol}{Kg} )

Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1

Plugging value in expression :

ΔTf = 1* 1.86 \frac{^0 C*Kg}{mol} * 0.907\frac{mol}{Kg} )

ΔTf = 1.69 ° C

Hence change in freezing point = 1.69 °C

5 0
3 years ago
How many moles of hydrogen are in 3. 06 × 10⁻³ g of glycine , c₂h₅no₂?.
Gala2k [10]

Answer:

n = 6.06 x 10^{-4} mol

Explanation:

n =?

m = 3.06 x 10-³ g

M (H5) = 5 x 1.01 (Since we only want hydrogen)

Atomic mass of C = 12.01

Atomic mass of H is 1,01, etc.

Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.

M = \frac{m}{n} ⇔ n = \frac{m}{M} ⇔ n = \frac{3.06 x 10^{-3} }{5,05} ⇔ n = 6.06 x 10^{-4} mol

Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.

8 0
2 years ago
The small bags of silica gel you often see in a new shoe box are placed there to control humidity. Despite its name, silica gel
Zinaida [17]

So we look equation for the free Gibbs free energy (ΔG) which depends on entalpy (ΔH), temperature (T) and entropy (ΔS):

ΔG = ΔH - TΔS

ΔG is negative (-) because the water absorption on the silica gel surface is a spontaneous process.

ΔH is negative (-) because the water absorption on the silica gel surface is a exothermic process (it releases heat and if you want to desorb the water form the silica gen you need to add heat which is a endothermic process).

ΔS is negative (-) because the water is adsorbed, so from disorderly state you take the water molecules and put them in a orderly state and by doing that you decrease the entropy.

6 0
3 years ago
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