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Elina [12.6K]
3 years ago
6

Two identical metal balls of radii 2.50

Physics
1 answer:
shutvik [7]3 years ago
3 0

Answer:

+1.33 × 10^{-7} C and -1.33 × 10^{-7} C respectively.

Explanation:

Electric potential (V) is the work done in moving a unit positive charge from infinity to a reference point within an electric field. It is measured in volts.

     V = \frac{kq}{r} ............. 1

where: k is a constant = 9 × 10^{9} Nm^{2} C^{-2}, q is the charge and r is the distance between the charges.

From equation 1,

   q = \frac{Vr}{k} ............... 2

The charge on each ball can be determined as;

given that; V = 1.2 × 10^{3}, k = 9 × 10^{9} Nm^{2} C^{-2} and r = 1.00 m.

From equation 2,

  q = \frac{1.2*10^{3} * 1.0}{9*10^{9} }

     = 1.33 × 10^{-7} C

Thus, the charge on the first ball is +1.33 × 10^{-7} C, while the charge on the second ball is -1.33 × 10^{-7} C.

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