Question

If the escalator pulls you up a slope of 30.0o​ ​ and moves with a velocity of 3.10m/s. What is the vertical component of your velocity? What is the horizontal component of your velocity?

Answer 1

Answer:

$1.55\ \text{m/s}$

$2.68\ \text{m/s}$

Explanation:

v = Velocity of the elevator = 3.1 m/s

$\theta$ = Angle of the slope = $30^{\circ}$

Vertical component is given by

$v_y=v\sin\theta\\\Rightarrow v_y=3.1\sin30^{\circ}\\\Rightarrow v_y=1.55\ \text{m/s}$

The vertical component of the velocity is $1.55\ \text{m/s}$.

Horizontal component is given by

$v_x=v\cos\theta\\\Rightarrow v_x=3.1\times \cos30^{\circ}\\\Rightarrow v_x=2.68\ \text{m/s}$

The horizontal component of the velocity is $2.68\ \text{m/s}$.