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erastova [34]
2 years ago
13

Two different liquids are mixed together. Which observation indicates that an exothermic chemical reaction has taken place?

Chemistry
1 answer:
Lilit [14]2 years ago
6 0

Answer:

rise in temp I think

Explanation:

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In which situation is no work considered to be done by a force?
Masja [62]

If the angle is either 0 or 180, that means that there is either negative or positive work, so A and D are not correct.

If the angle is 45, then there is still some work involved.

The only option where there is no work done by a force is B. when the angle is between the force and displacement is 90. 

7 0
3 years ago
Read 2 more answers
What is the [H+] of a solution with a pH of 9.40?
LiRa [457]

Answer:

a) 3.98 x 10^-10

Explanation:

Hello,

In this case, for the given pH, we can compute the concentration of hydronium by using the following formula:

pH=-log([H^+])

Hence, solving for the concentration of hydronium:

[H^+]=10^{-pH}=10^{-9.40}\\

[H^+]=3.98x10^{-10}M

Therefore, answer is a) 3.98 x 10^-10

Best regards.

4 0
3 years ago
Which of the following is a valid unit for specific heat?
Marysya12 [62]

Answer:

The answer is D

Explanation:

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!
kondor19780726 [428]
<h3>Answer:</h3>

0.424 J/g °C

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Thermochemistry</u>

Specific Heat Formula: q = mcΔT

  • q is heat (in Joules)
  • m is mass (in grams)
  • c is specific heat (in J/g °C)
  • ΔT is change in temperature
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] m = 38.8 g

[Given] q = 181 J

[Given] ΔT = 36.0 °C - 25.0 °C = 11.0 °C

[Solve] c

<u>Step 2: Solve for Specific Heat</u>

  1. Substitute in variables [Specific Heat Formula]:                                             181 J = (38.8 g)c(11.0 °C)
  2. Multiply:                                                                                                             181 J = (426.8 g °C)c
  3. [Division Property of Equality] Isolate <em>c</em>:                                                         0.424086 J/g °C = c
  4. Rewrite:                                                                                                             c = 0.424086 J/g °C

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.424086 J/g °C ≈ 0.424 J/g °C

6 0
2 years ago
What is the name for SO2
Tanzania [10]
Sulphur Dioxide. Toxic. Don't eat it.
7 0
3 years ago
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