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erastova [34]
3 years ago
13

Two different liquids are mixed together. Which observation indicates that an exothermic chemical reaction has taken place?

Chemistry
1 answer:
Lilit [14]3 years ago
6 0

Answer:

rise in temp I think

Explanation:

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write a molecular, ionic, and net ionic equation for the reaction between solid magnesium carbonate and sulfuric acid.
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Answer:

How to Write the Net Ionic Equation for H2SO4 + MgCO3 = MgSO4 + H2O + CO2 -

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3 years ago
Help me plx.
lisov135 [29]

Answer:

DNA, or deoxyribonucleic acid, is the hereditary material in humans and almost all other organisms. Nearly every cell in a person's body has the same DNA.

EXPLANATION: SO THE CORRECT ANSWER IS

"NUCLEIC ACID"

7 0
3 years ago
What is the molarity of a 250ml KCl solution made by diluting 175mL of a 3.00 M solution?
Crank

Answer:

2.1 M

Explanation:

The dilution equation is M_{s} V_{s}  = M_{d} V_{d}.

M_{s} = the molarity of the sock solution

V_{s} = the volume of the sock solution

M_{d} = the molarity of the diluted solution

V_{d} = the volume of the diluted solution

The stock solution would be what is doing the diluting, so "175 mL of a 3.00 M solution". So M_{s} = 3.00 M. Then: Converting 175 mL to liters: 175 mL * \frac{1 L}{1000mL} = 0.175 L (This is V_{s})

And converting 250 mL KCl to liters: 250 mL * \frac{1 L}{1000mL} = 0.250 L (This will be V_{d})

Then, we plug in our given into the dilution equation, resulting in:

3.00 M * 0.175 L = M_{d} * 0.250 L (divide both sides by 0.250 L, in order to get M_{d} by itself)

\frac{3.00 M * 0.175 L}{0.250 L} = M_{d}

M_{d} = 2.1 M

So, the molarity of 250 mL KCl made by diluting 175 mL of a 3.0 M solution would be 2.1 M (mol/L).

Hopefully this helped you understand the topic a little bit better. I just finished molarity and dilutions in Chemistry last week. Good luck!

4 0
3 years ago
Which of the following is not a rock? a. granite b. shale c. marble d. diamond
Savatey [412]
Diamond is not a rock it is a mineral. 
5 0
3 years ago
Read 2 more answers
An experimenter found that for the hydrolysis of lactose, ΔH° = +0.44 kJ mol–1 and ΔS° = +0.031 kJ mol–1 K–1. ΔG°for this reacti
Ksivusya [100]

Answer:

ΔG° = -8.8 kJ/mol

Explanation:

The standard Gibbs free energy of reaction (ΔG°) can be calculated using the following expression.

ΔG° = ΔH° - T.ΔS°

where,

ΔH°: standard enthalpy of reaction

T: absolute temperature

ΔS°: standard entropy of reaction

At 298 K (the temperature that is usually used), ΔG° for the hydrolysis of lactose is:

ΔG° = ΔH° - T.ΔS°

ΔG° = 0.44 kJ/mol - 298 K × 0.031 kJ/mol.K

ΔG° = -8.8 kJ/mol

7 0
3 years ago
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