What is sound energy? List three examples of sound energy that you experienced today.

If you know all of the forces acting on a moving object, can you tell in which direction the object is moving? if the answer is

Montano1993 [528]

No, knowing all the forces is not enough to know the direction of motion.

<h3>How to use Newton's laws?</h3>

The second Newton's law states that:

F = m*a

This says <u><em>"force equals mass times acceleration".</em></u>

Where acceleration is the rate of change of the speed. From that equation, we conclude that the acceleration is in the same direction that the net force.

So, if we know all the forces acting on an object, we know the net force acting on it, then we know the direction of the acceleration.

<h3>Is this enough to know the direction in which it is moving?</h3>

No, the object does not need to move in the same direction than its acceleration, the direction of motion will also depend on the initial velocity of the object (if it is initially moving with constant speed).

If we don't know that, we can't find the direction of motion.

An example of this can be a car going at 100km/h east-wise.

Then we apply a net force due west, then we have an acceleration due west. But as the initial direction of motion was east, the car will still move to the east, but the velocity will decrease gradually.

So as you can see in that example, we need to know the initial velocity to know the direction in which the object is moving.

If you want to know more about acceleration, you can read:

brainly.com/question/605631

8 0

2 years ago

After watching the video below and based on your personal experiences, is there a difference

jek_recluse [69]

Based on my personal experiences, I believe that there is a difference between areas in precision of control because there are different part of the brain that controls the functions of the body.

<h3>What is the difference between left-handed and right-handed people?</h3>

From the standpoint of brain lateralization, differences do exist such as based on experience such as handedness or specific skills such as playing a guitar.

Note that Left-handers are said to have reduced or little lateralized brains, which tells us that the two halves of the brain are little different than as seen in the right-handers.

Therefore, I can say that based on my personal experiences, I believe that there is a difference between areas in precision of control because there are different part of the brain that controls the functions of the body.

Learn more about brain from

brainly.com/question/1247675

#SPJ1

3 0

2 years ago

A motion sensor emits sound, and detects an echo 0.0115 s after. A short time later, it again emits a sound, and hears an echo a

Mekhanik [1.2K]

Answer:

1.17 m

Explanation:

From the question,

s₁ = vt₁/2................ Equation 1

Where s₁ = distance of the reflecting object for the first echo, v = speed of the sound in air, t₁ = time to dectect the first echo.

Given: v = 343 m/s, t = 0.0115 s

Substitute into equation 1

s₁ = (343×0.0115)/2

s₁ = 1.97 m.

Similarly,

s₂ = vt₂/2.................. Equation 2

Where s₂ = distance of the reflecting object for the second echo, t₂ = Time taken to detect the second echo

Given: v = 343 m/s, t₂ = 0.0183 s

Substitute into equation 2

s₂ = (343×0.0183)/2

s₂ = 3.14 m

The distance moved by the reflecting object from s₁ to s₂ = s₂-s₁

s₂-s₁ = (3.14-1.97) m = 1.17 m

7 0

3 years ago

Read 2 more answers

Sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motionstays in motion with the sam

Lera25 [3.4K]

Answer:

D

Explanation:

Newtons first law states that if an object is at rest it will stay at rest only if an unbalanced force acts on it. As well as if an object is in motion it will stay in motion unless an unbalanced force acts on it.

Ps- The object will stay moving in the same speed and direction.

5 0

2 years ago

Determine the gravitational field 300km above the surface of the earth. How does this compare to the field on the earth's surfac

Serjik [45]

The strength of the gravitational field is given by:
$g= \frac{GM}{r^2}$
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.

In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
$r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m$

And now we can use the previous equation to calculate the field strength at that altitude:
$g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(6.67 \cdot 10^6 m)^2} = 8.95 m/s^2$

And we can see this value is a bit less than the gravitational strength at the surface, which is $g_s = 9.81 m/s^2$ .

4 0

3 years ago