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3 years ago

If one wave of 10m amplitude meets constructively with another wave of amplitude 20m, what is the new amplitude?

1 answer:

8 0

The answer is 30m. If one wave of 10m amplitude meets constructively with another wave of amplitude 20m, the new amplitude is 30m. When wave interfere constructively, their amplitudes are added. So the amplitude in this case is 10 m+20 m=30 m .

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natita [175]

Answer:

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Explanation:

3 0

3 years ago

Give an example of a vertical motion with a positive velocity and a negative acceleration. Give an example of a vertical motion

Assoli18 [71]

Answer:

An example of positive velocity is throwing a ball upwards

An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height

Explanation:

In a vertical movement the acceleration is always downwards, therefore negative since it is created by the attraction of the Earth on the body.

An example of positive velocity is throwing a ball upwards

An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height

7 0

4 years ago

A 20.0 Ω, 15.0 Ω, and 7.00 Ω resistor are connected in parallel to an emf source. A current of 7.00 A is in the 15.0 Ω resistor.

Lady bird [3.3K]

PART A)

Equivalent resistance in parallel is given as

$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$

now we have

$\frac{1}{R} = \frac{1}{20} + \frac{1}{15} + \frac{1}{7}$

$R = 3.85 ohm$

PART B)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

$V = iR$

As we know i = 7 A current flows through 15 ohm resistance

$V = (7 A)(15 ohm) = 105 volts$

PART C)

Similarly ohm's law for 20 ohm resistance we can say

$V = iR$

$105 = i(20 ohm)$

$i = 5.25 A$

3 0

4 years ago

Read 2 more answers

When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction g

BartSMP [9]

To solve this problem we will apply the concepts related to the double slit-experiment. For which we will relate the distance between the Slits and the Diffraction Angle with the order of the bright fringe and the wavelength, this is mathematically given as,

$d sin\theta = m\lambda$