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DanielleElmas [232]
3 years ago
6

Write an application that solicits and inputs three integers from the user and then displays the sum, average, product, smallest

, and largest of the three numbers. You may use any Java input and output method you want, for example the JOptionPane class or the Scanner class.You must use only integer arithmetic for your calculations.Use the numbers 7, 3, and 5, in that order, for your program execution that you will submit. Although your program must be written to handle any three integers in general, these specific values must be used for this program submission, in this order.You may use the Windows Command Prompt command line interface or any Java IDE you choose to compile and execute your program.
Engineering
1 answer:
Ganezh [65]3 years ago
6 0

Answer:

3423=6^H

Explanation:

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A center-point bending test was performed on a 2 in. x d in. wood lumber according to ASTM D198 procedure with a span of 4 ft an
Zigmanuir [339]

Answer:

3.03 INCHES

Explanation:

According to ASTM D198 ;

Modulus of rupture = ( M / I ) * y  ----- ( 1 )

M ( bending moment ) = R * length of span / 2

                                     = (120 * 10^3 ) * 48 / 2 = 288 * 10^4 Ib-in

I ( moment of inertia ) = bd^3 / 12

                                    = ( 2 )*( d )^3  / 12 =  2d^3 / 12

b = 2 in ,  d = ?

length of span = 4 * 12 = 48 inches

R = P  / 2 =  240 * 10^3 / 2 =   120 * 10^3 Ib

y ( centroid distance ) = d / 2  inches

back to equation ( 1 )

( M / I ) * y

940.3 ksi = ( 288 * 10^4 / 2d^3 / 12 ) * d / 2

                = ( 288 * 10^4 * 12 ) / 2d^3 )  * d / 2

940300  = 34560000* d / 4d^3

4d^3 ( 940300 ) = 34560000 d  ( divide both sides with d )

4d^2 = 34560000 / 940300

d^2 = 9.188   ∴ Value of d ≈ 3.03 in

8 0
3 years ago
Technician A says that a radio may be able to receive AM signals, but not FM signals if the antenna is defective. Technician B s
DIA [1.3K]

The response to whether the statements made by both technicians are correct is that;

D: Neither Technician A nor Technician B are correct.

<h3>Radio Antennas</h3>

In radios, antennas are the means by which signals to the sought frequency be it AM or FM are received.

Now, if the antenna is bad, it means it cannot pick any radio frequency at all and so Technician A is wrong.

Now, most commercial antennas usually come around a resistance of 60 ohms and so it is not required for a good antenna to have as much as 500 ohms resistance and so Technician B is wrong.

Read more about Antennas at; brainly.com/question/25789224

3 0
2 years ago
Pls help and solve this problem. I don't have an idea to solve this.
lions [1.4K]

Answer:

MIS HIEVOSTES bbbbbbbbbbbb MIS HUEVOTES

7 0
2 years ago
Describe at least one way you take advantage or could take advantage of each of the different forms of energy
Scorpion4ik [409]

Answer:

Kinetic energy can be used to develop electric energy which can be used as electricity.

Explanation:

The kinetic energy can be harnessed; much like some hydro power technologies harness water movement. A way to convert this kinetic energy into electric energy is through piezoelectric. By applying a mechanical stress to a piezoelectric crystal or material an electric current will be created and can be harvested.

Kinetic energy is also generated by the human body when it is in motion. Studies have also been done using kinetic energy and then converting it to other types of energy, which is then used to power everything from flashlights to radios and more.

4 0
2 years ago
1. If you look at a reaction equation for a Fischer esterification reaction, you cannot tell where the oxygen comes from (acid o
Yanka [14]

Answer:

Explained

Explanation:

In the experiment, an (18)O-labelled alcohol R('18)OH is used with normal unlabeled carboxylic acid RC(16)O2H:

The esterification reaction is:  

(note: the bracketed values are atomic masses)

RC(16)O_2H + R'(18)OH => RC16O18OR' + H_2(16)O

Since the alcohol is the nucleophile in this nucleophilic substitution reaction, it adds to the carbonyl group of the carboxylic acid and the (18)O atom becomes incorporated into the ester product, while the (16)OH group of the carboxylic acid is expelled as H_2(16)O.

By using mass spectroscopy to measure the mass of the ester and water products, it can be shown that each ester molecule contains one (18)O atom and one (16)O atom, while the water molecules contains only (16)O atoms.

This would prove unequivocally that the ester contains one O atom from the carboxylic acid and one O atom from the alcohol, while the water contains only O atoms from the carboxylic acid.

7 0
3 years ago
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