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Anni [7]
2 years ago
7

Describe at least one technological application of radioactive decay that can benefit human health.

Physics
2 answers:
VLD [36.1K]2 years ago
6 0

Answer:

Radiotherapy

Explanation:

geniusboy [140]2 years ago
5 0

Answer:Describe at least one technological application of radioactive decay that can benefit human health. Radioisotopes are used in medicine as tracers to detect and diagnose medical problems. Radioisotopes are also used in radiation therapy to treat cancer.

Explanation:

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What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K? The latent heat of vaporization
GREYUIT [131]

Answer : The mass of a sample of water is, 888.89 grams

Explanation :

Latent heat of vaporization : It is defined as the amount of heat energy released or absorbed when the liquid converted to vapor at atmospheric pressure at its boiling point.

Formula used :

q=L\times m

where,

q = heat = 2000 kJ = 2\times 10^6J       (1 kJ = 1000 J)

L = latent heat of vaporization of water = 2.25\times 10^6J/kg

m = mass of sample of water = ?

Now put all the given values in the above formula, we get:

2\times 10^6J=(2.25\times 10^6J/kg)\times m

m=0.88889kg=888.89g       (1 kg = 1000 g)

Therefore, the mass of a sample of water is, 888.89 grams

3 0
4 years ago
A rock with a mass of 25 kg has a weight of 40.8 n on the moon. what is the value of the acceleration of gravity (g) on the moon
zaharov [31]
Mass m = 25 Kg;  Force = Weight = mg   Force = ma  but a = g

          F = 40.8 N

Required: gravity g = ?

                F = mg

                g = F/m

                g = 40.8 N/25 Kg

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7 0
4 years ago
An attempt to explain observations of the natural world is
Ludmilka [50]
Should be scientific theory
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An atom that loses an electron is called a/an
seraphim [82]
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3 0
3 years ago
A 2640-Hz sound source is moving at 15.0m/s toward a stationary observer. What is the frequency heard by the observer if the spe
Dvinal [7]

Answer:

The frequency heard by the observer is 2760.73 hertz.                 Explanation:

Frequency of source, f = 2640 Hz

Velocity of source, v_s=15\ m/s

The speed of sound, v = 343 m/s

Let f' is the frequency heard by the observer. According to Doppler's effect, the frequency of the observer is given by :

f'=\dfrac{fv}{v-v_s} (as the source is moving towards observer)

f'=\dfrac{2640\times 343}{343-15}  

f' = 2760.73 Hz

So, the frequency heard by the observer is 2760.73 hertz. Hence, this is the required solution.                              

8 0
4 years ago
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