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Studentka2010 [4]
3 years ago
15

What are the odds of nonsmokers developing cardiovascular disease when compared to smokers?

Physics
2 answers:
77julia77 [94]3 years ago
6 0
The probability ("odds") is smaller for nonsmokers when compared
to smokers.

If we had as much hard, reliable, repeatable, scientific evidence linking
cardiovascular disease with visits to the Empire State Building as we have
linking it with smoking, the Empire State Building would have been torn down
50 years ago.
insens350 [35]3 years ago
3 0

Answer choices are:

a. Nonsmokers are four times more likely to develop cardiovascular disease.

b. Nonsmokers are twice as likely to develop cardiovascular disease.

c. Nonsmokers and smokers are equally likely to develop cardiovascular disease.

d. Nonsmokers are half as likely to develop cardiovascular disease.

____________________________________________________________

Correct answer choice is:

d. Nonsmokers are half as likely to develop cardiovascular disease.

____________________________________________________________

Explanation:

The consequence of previous or existing smoking on specific CVD risk parameters such as blood pressure and cholesterol appears to be of clinically trivial importance in personalities aged 46 years. In additional terms, smoking appears to be beyond all an unconventional risk factor for CVD in the working-age people. Stopping smoking in working age may thus decrease estimated CVD risk approximately to the equivalent level as personages who have never smoked.

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If many household substances classify as acids or bases what is the ph scale
bekas [8.4K]

Answer: Some household items that contain acids include: yogurt, vinegar,lemon juice, citric acid, apples, jelly, pineapples, cranberry sauce, milk, and batteries and In chemistry, pH is a scale used to specify how acidic or basic a water-based solution is. Acidic solutions have a lower pH, while basic solutions have a higher pH. At room temperature, pure water is neither acidic nor basic and has a pH of 7.

4 0
3 years ago
The change in momentum of an object is equal to the ____________ that acts on it.
meriva

Answer : The change in momentum of an object is equal to the impulse that acts on it.

Explanation :

Change in momentum : The change in momentum of an object is the product of the mass and the change in velocity of an object.

The formula of change in momentum is,

\Delta p=m\times \Delta v

Impulse : An impulse of an object is the product of the force applied on an object and the change in time. Impulse is also equivalent to the change in momentum of  an object.

J=F\times \Delta t

Proof :

J=F\times \Delta t\\\\J=(m\times a)\times \Delta t\\\\J=m\times (a\times \Delta t)\\\\J=m\times \Delta v=\Delta p

Hence, the change in momentum of an object is equal to the impulse that acts on it.

3 0
3 years ago
Read 2 more answers
A balloon filled with helium occupies 20.0 l at 1.50 atm and 25.0◦
bija089 [108]
At stp (standard temperature and pressure), the temperature is T=0 C=273 K and the pressure is p=1.00 atm. So we can use the ideal gas law to find the number of moles of helium:
pV=nRT
where p is the pressure (1.00 atm), V the volume (20.0 L), n the number of moles, T the temperature (273 K) and R=0.082 atm L K^{-1} mol^{-1} the gas constant. Using the numbers and re-arranging the formula, we can calculate n:
n= \frac{pV}{RT}= \frac{(1.00atm)(20.0L)}{(0.082 LatmK^{-1}mol^{-1})(273 K)}=0.89 mol
5 0
3 years ago
What is the largest possible magnitude of the acceleration of the electron due to the magnetic field?
Alina [70]
Thank you for posting your question here at brainly. But your question seems incomplete. I will assume you based the situation below:

<span>An electrons moves at 2.0x10^6 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.4x10^-2 T. 

The </span> largest possible magnitude of the acceleration of the electron due to the magnetic field is <span>= 2.6 × 10 ¹⁶ m / s ²</span>
6 0
3 years ago
A soccer player kicks a soccer ball with a force of 1.8 N. If the mass of the ball is .43 kg. How fast will the ball accelerate?
Vesnalui [34]

Answer:

The acceleration of the ball is 4.18 [m/s^2]

Explanation:

By Newton's second law we can find the acceleration of the ball

F = m*a\\where:\\F = force applied [N] or [kg*m/s^2]\\m = mass of the ball [kg]\\a = acceleration [m/s^s]

Now we have:

a = F/m\\a = \frac{1.8 [kg*m/s^s]}{0.43[kg]} \\a = 4.18 [kg]

4 0
3 years ago
Read 2 more answers
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