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Studentka2010 [4]
3 years ago
15

What are the odds of nonsmokers developing cardiovascular disease when compared to smokers?

Physics
2 answers:
77julia77 [94]3 years ago
6 0
The probability ("odds") is smaller for nonsmokers when compared
to smokers.

If we had as much hard, reliable, repeatable, scientific evidence linking
cardiovascular disease with visits to the Empire State Building as we have
linking it with smoking, the Empire State Building would have been torn down
50 years ago.
insens350 [35]3 years ago
3 0

Answer choices are:

a. Nonsmokers are four times more likely to develop cardiovascular disease.

b. Nonsmokers are twice as likely to develop cardiovascular disease.

c. Nonsmokers and smokers are equally likely to develop cardiovascular disease.

d. Nonsmokers are half as likely to develop cardiovascular disease.

____________________________________________________________

Correct answer choice is:

d. Nonsmokers are half as likely to develop cardiovascular disease.

____________________________________________________________

Explanation:

The consequence of previous or existing smoking on specific CVD risk parameters such as blood pressure and cholesterol appears to be of clinically trivial importance in personalities aged 46 years. In additional terms, smoking appears to be beyond all an unconventional risk factor for CVD in the working-age people. Stopping smoking in working age may thus decrease estimated CVD risk approximately to the equivalent level as personages who have never smoked.

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Define thermal conductivity.
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A measure of the ability of a material to transfer heat.

Explanation:

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A test tube of length L and cross-sectional area A is submerged in water with the open end down so that the edge of the tube is
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Answer:

if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

Explanation:

The air in the tube can be considered an ideal gas,

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In that case we have the tube in the air where the pressure is P1 = P_atm, then we introduce the tube to the water to a depth H

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         P₂ = P_atm + ρ g H

Let's write the gas equation for the colon

            P₁ V₁ = P₂ V₂

            P_atm V₁ = (P_atm + ρ g H) V₂

             V₂ = V₁    P_atm / (P_atm + ρ g h)

If the air obeys Boyle's law e; volume within the had must decrease due to the increase in pressure, if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

The main assumption is that the temperature during the experiment does not change

6 0
3 years ago
How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s2
soldier1979 [14.2K]
∑F = ma = (90 kg)(1.2 m/s²) = 108 N = 100 N (1 significant digit)

3 0
3 years ago
Read 2 more answers
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