3 years ago

Help????????????????????

Physics

1 answer:

Elan Coil [88]3 years ago

5 0

A. Six electrons
B. six protons
C. they are composed of two up quarks and one down quark.

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A car traveling west at 70 miles per hour for 3 hours covers a distance of

gtnhenbr [62]

70x3=210 mph... its that easy

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3 years ago

A solid ball has a radius of 2cm and a length of 7cm. It has a density of 3.1g/cm3

Iteru [2.4K]

Density is mass divided by volume, you would have to solve for the volume of the ball and rearrange the equation to density divided by volume equals mass

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3 years ago

Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a fa

RoseWind [281]

If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is

F' = G (5m₁) (2m₂) / d²

F' = 10 Gm₁m₂ / d²

but this is really just F' = 10F. So J is the correct choice.

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2 years ago

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A car has a force of 2000N and a mass of<br> 1000kg. What is the acceleration of the<br> car?

yan [13]

Answer:

100

Explanation:

by dividing 2000N and 1000kg.

5 0

3 years ago

When landing after a spectacular somersault, a 35.0 kg gymnast decelerates by pushing straight down on the mat. calculate the fo

Sliva [168]

The deceleration experienced by the gymnast is the 9 times of the acceleration due to gravity.

Now from Newton`s first law, the net force on gymnast,

$F_{net} =F-W=ma$

Here, W is the weight of the gymnast and a is the acceleration experienced by the gymnast ( $9\times g$ acceleration due to gravity)

Therefore,

$F= ma+W$ OR $F=ma+mg=m(g+a)$

Given $m = 30 kg$ and $a=9\times g=9\times 9.8 m/s^{2} =88.2 m/s^{2}$

Substituting these values in above formula and calculate the force exerted by the gymnast,

$F=(40 kg) (88.2 m/s^{2} +9.8 m/s^{2} )$

$F=3.537\times10^{3}N$

6 0

3 years ago