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iVinArrow [24]
3 years ago
8

Help????????????????????

Physics
1 answer:
Elan Coil [88]3 years ago
5 0
A. Six electrons
B. six protons
C. they are composed of two up quarks and one down quark.
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Definition of the following word <br>Work ,measurement​
garri49 [273]

Answer:

measurements

Explanation:

Measurement is the assignment of a number to a characteristic of an object or event, which can be compared with other objects or events. The scope and application of measurement are dependent on the context and discipline.

7 0
3 years ago
Read 2 more answers
The gamma ray released by each decay carries 140kev of energy. find the total energy e released by decays in the 2 hours.
olya-2409 [2.1K]
First, we would need to know the decaying isotope.
Next, we use the decay formula
A = Ao e^(-kt)
After determining the remaining amount after two hours, the decay reaction can be used to determine the number of gamma rays released. If the given is in terms of mole, then the total energy is
E = 140n KeV where n is the number of moles of gamma rays released
8 0
3 years ago
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What is the stopping distance at night for a passenger vehicle traveling at 50 mph?
RideAnS [48]
Bgvuob ujimka  balcentra
7 0
3 years ago
A fair ground ride spins its occupants inside a flying saucer-shaped container. if the horizontal circular path the riders follo
Licemer1 [7]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below is the solution:

 <span>centripetal accel = 1.5*g 
ω²r = 1.5*9.8m/s² 
ω² * 8m = 14.7 m/s² 
ω = 1.36 rad/s * 1rev/2πrads * 60s/min = 12.9 rpm</span>

6 0
3 years ago
In a nuclear reactor, each atom of uranium (of atomic mass 235 u) releases about 200 MeV when it fissions. What is the change in
Ket [755]

Answer:

0.002372187708 kg

Explanation:

Each atom of Uranium 235 releases 200 MeV = 200×10⁶×1.60218×10⁻¹⁹

= 200×1.60218×10⁻¹³ Joule

Number of atoms in a 2.6 kg sample mass = (2.6/0.235)×6.02214076×10²³

⇒Number of atoms in a 2.6 kg sample mass = 66.627×10²³ atoms

Change in energy = Change in mass / (speed of light)²

ΔE = Δmc²

⇒200×1.60218×10⁻¹³×66.627×10²³ = Δm×(3×10⁸)²

⇒Δm = 200×1.60218×10⁻¹³×66.627×10²³/(3×10⁸)²

⇒Δm = 2372.187708×10⁻⁶ kg

∴Change in mass = 0.002372187708 kg

7 0
3 years ago
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