Answer:
Period of one vibration = 0.00215 second (Approx.)
Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)
Explanation:
Given:
Frequency of wave = 466 Hz
Find:
Period of one vibration
Wavelength {Is speed of sound is 343 m/s]
Computation:
Period of one vibration = 1/F
Period of one vibration = 1 / 466
Period of one vibration = 0.00215 second (Approx.)
Wavelength = Velocity / Frequency
Wavelength {Is speed of sound is 343 m/s] = 343 / 466
Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)
The vertical component of the force exerted by the hi.nge on the beam is 114.77 N.
<h3>Tension in the cable</h3>
Apply the principle of moment and calculate the tension in the cable;
Clockwise torque = TL sinθ
Anticlockwise torque = ¹/₂WL
TL sinθ = ¹/₂WL
T sinθ = ¹/₂W
T = (W)/(2 sinθ)
T = (29 x 9.8)/(2 x sin57)
T = 169.43 N
<h3>Vertical component of the force</h3>
T + F = W
F = W - T
F = (9.8 x 29) - 169.43
F = 114.77 N
Thus, the vertical component of the force exerted by the hi.nge on the beam is 114.77 N.
Learn more about tension here: brainly.com/question/24994188
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I believe the answer is the mass of the object and the speed at which it is moving.
There are 60 seconds in a minute.
This means that 5 minutes would be 60 times 5.
60×5 = 300
There are 300 seconds in 5 minutes.