Answer:
![\frac{R_2}{R_1}=\frac{A_1}{A_2}\\\frac{R_4}{R_3}=\frac{A_3}{A_4}](https://tex.z-dn.net/?f=%5Cfrac%7BR_2%7D%7BR_1%7D%3D%5Cfrac%7BA_1%7D%7BA_2%7D%5C%5C%5Cfrac%7BR_4%7D%7BR_3%7D%3D%5Cfrac%7BA_3%7D%7BA_4%7D)
Explanation:
The resistance of a conductor is directly proportional to its length and is inversely proportional to its cross-sectional area, this dependence is given by:
![R=\frac{\rho L}{A}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B%5Crho%20L%7D%7BA%7D)
is the material's resistance, L is the legth and A is the cross-sectional area.
For the first and second coils, we have:
![R_1=\frac{\rho L}{A_1}\\R_2=\frac{\rho L}{A_2}\\\rho L=R_1A_1\\\rho L=R_2A_2\\R_1A_1=R_2A_2\\\frac{R_2}{R_1}=\frac{A_1}{A_2}](https://tex.z-dn.net/?f=R_1%3D%5Cfrac%7B%5Crho%20L%7D%7BA_1%7D%5C%5CR_2%3D%5Cfrac%7B%5Crho%20L%7D%7BA_2%7D%5C%5C%5Crho%20L%3DR_1A_1%5C%5C%5Crho%20L%3DR_2A_2%5C%5CR_1A_1%3DR_2A_2%5C%5C%5Cfrac%7BR_2%7D%7BR_1%7D%3D%5Cfrac%7BA_1%7D%7BA_2%7D)
For the third and fourth coils, we have:
![R_3=\frac{\rho L'}{A_3}\\R_4=\frac{\rho L'}{A_4}\\\rho L'=R_3A_3\\\rho L'=R_4A_4\\R_3A_3=R_4A_4\\\frac{R_4}{R_3}=\frac{A_3}{A_4}](https://tex.z-dn.net/?f=R_3%3D%5Cfrac%7B%5Crho%20L%27%7D%7BA_3%7D%5C%5CR_4%3D%5Cfrac%7B%5Crho%20L%27%7D%7BA_4%7D%5C%5C%5Crho%20L%27%3DR_3A_3%5C%5C%5Crho%20L%27%3DR_4A_4%5C%5CR_3A_3%3DR_4A_4%5C%5C%5Cfrac%7BR_4%7D%7BR_3%7D%3D%5Cfrac%7BA_3%7D%7BA_4%7D)
Answer:
Yes is large enough
Explanation:
We need to apply the second Newton's Law to find the solution.
We know that,
![F= ma](https://tex.z-dn.net/?f=F%3D%20ma)
And we know as well that
![a= \frac{v}{t}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7Bv%7D%7Bt%7D)
Replacing the aceleration value in the equation force we have,
![F= \frac{mv}{t}](https://tex.z-dn.net/?f=F%3D%20%5Cfrac%7Bmv%7D%7Bt%7D)
Substituting our values we have,
![F= \frac{(0.060)(55)}{4*10^{-3}}](https://tex.z-dn.net/?f=F%3D%20%5Cfrac%7B%280.060%29%2855%29%7D%7B4%2A10%5E%7B-3%7D%7D)
![F=825N](https://tex.z-dn.net/?f=F%3D825N)
The weight of the person is then,
![W = mg](https://tex.z-dn.net/?f=W%20%3D%20mg)
![W = (60)(9.8) = 558N](https://tex.z-dn.net/?f=W%20%3D%20%2860%29%289.8%29%20%3D%20558N)
<em>We can conclude that force on the ball is large to lift the ball</em>
Answer:
A
Explanation:
because you cannot seperate the matter duhhh hahha
Answer:
0.42°
Explanation:
Using Snell's law of refraction which states that the ratio of the angle of sin of incidence to angle of sine of refraction is equal to a constant for a given pair of media. Mathematically,
Sin(i)/sin(r) = n
n is the refractive index of the medium
FOR VIOLET LIGHT:
n = 2.46
i = 51°
r = ?
To get r, we will use the Snell's law formula.
2.46 = sin51°/sinr
Sinr = sin51°/2.46
Sinr = 0.316
r = sin^-1(0.316)
rv = 18.42°
FOR RED LIGHT:
n = 2.41
i = 51°
r = ?
To get r, we will use the Snell's law formula.
2.41 = sin51°/sinr
Sinr = sin51°/2.41
Sinr = 0.323
r = sin^-1(0.323)
rd = 18.84°
The angular separation between these two colors of light in the refracted ray will be the difference between there angle of refraction.
Angular separation = rd - rv
= 18.84° - 18.42°
= 0.42°
Answer:
The induced emf in the coil is ![e_t = 25\ V](https://tex.z-dn.net/?f=e_t%20%3D%2025%5C%20%20V)
Explanation:
From the question we are told that
The magnitude of the emf for a single loop is ![e = 5.0 V](https://tex.z-dn.net/?f=e%20%3D%20%205.0%20V)
The number of turn of the new wire is N = 5
The magnitude of the emf induced in the coil is
![e_t = N * e](https://tex.z-dn.net/?f=e_t%20%3D%20%20N%20%2A%20e)
substituting value
![e_t = 5 * 5](https://tex.z-dn.net/?f=e_t%20%3D%205%20%2A%205)
![e_t = 25\ V](https://tex.z-dn.net/?f=e_t%20%3D%2025%5C%20%20V)