All categories

3 years ago

Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.

2 answers:

5 0

With reference to the solutions, following things may be noted
1) Homogeneous solutions comprises of single phase.
2) Heterogeneous solution comprises of more than one phase.
3) in colloidal solution, solute is evenly distributed in solvent. in such system, it is difficult to separate solute and solvent.
4) in suspension, there is an uneven distribution of solute in solvent. In such system, solute and solvent gets separated on standing long.

Blood is a homogeneous and colloidal solution,
Salad dressing is a heterogeneous and suspension solution.

Murljashka [212]3 years ago

5 0

blood: heterogeneous and suspension

salad dressing: heterogeneous and suspension

You might be interested in

oth hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you opene

Ksju [112]

Answer: Odor of ammonia would we detect first on the other side of the room.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{M_{NH_3}}{M_{H_2S}}}$

$\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{17.031}{34.1}}$

$\frac{Rate_{H_2S}}{Rate_{NH_3}}=0.71$

Thus the odor of ammonia would we detect first on the other side of the room as the rate of effusion of ammonia would be faster as it has low molecular weight as compared to hydrogen sulphide.

5 0

3 years ago

Read 2 more answers

Determine the direction that each of the reactions will progress. Assume that the reactants and products are present in equimola

xxMikexx [17]

Answer:

It would move either left or right

Explanation: Taking assumption that,

Fructose + ATP fructose - 6 - phosphate + ADP (The standard free energy of hydrolysis for fructose-6-phosphate is - 15.9 kJ/mol.) 3 - phosphoglycerate + ATP 1,3 - bisphosphoglycerate + ADP (The standard free energy of hydrolysis for 1,3-bisphosphoglycerate is - 4 9.3 kJ/mol.) pyruvate + ATP phosphoenolpyruvate + ADP (The standard free energy of hydrolysis for phosphoenolpyruvate -is -61.9 kJ/mol.)

8 0

3 years ago

The starting position of this object is m. The object is traveling at a velocity of m/s.

Ad libitum [116K]

Answer:

The starting position of this object is 3 m

The object is traveling at a velocity of 3 m/s

Explanation:

6 0

3 years ago

Read 2 more answers

Which of the following possess the greatest concentration of hydroxide ions?

jek_recluse [69]

Answer : The correct option is (d) a solution of 0.10 M NaOH

Explanation :

(a) a solution of pH 3.0

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-3.0=11$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$11=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-11}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-11}M$

(b) a solution of 0.10 M $NH_3$

As we know that 1 mole of $NH_3$ is a weak base. So, in a solution it will not dissociates completely.

So, the $OH^-$ concentration will be less than 0.10 M

(c) a solution with a pOH of 12.

We have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$12=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-12}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-12}M$

(d) a solution of 0.10 M NaOH

As we know that $NaOH$ is a strong base. So, it dissociates to give $Na^+$ ion and $OH^-$ ion.

So, 0.10 M of $NaOH$ in a solution dissociates to give 0.10 M of $Na^+$ ion and 0.10 M of $OH^-$ ion.

Thus, the $OH^-$ concentration is, 0.10 M

(e) a $1\times 10^{-4}M$ solution of $HNO_2$

As we know that 1 mole of $HNO_2$ in a solution dissociates to give 1 mole of $H^+$ ion and 1 mole of $NO_2^-$ ion.

So, $1\times 10^{-4}M$ of $HNO_2$ in a solution dissociates to give $1\times 10^{-4}M$ of $H^+$ ion and $1\times 10^{-4}M$ of $NO_2^-$ ion.

The concentration of $H^+$ ion is $1\times 10^{-4}M$

First we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (1.0\times 10^{-4})$

$pH=4$

Now we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-4=10$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$10=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-10}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-10}M$

From this we conclude that, a solution of 0.10 M NaOH possess the greatest concentration of hydroxide ions.

Hence, the correct option is (d)

3 0

3 years ago

A soft drink contains 46 g of sugar(sucrose C12H22O11) how many sugar molecules are present?

professor190 [17]

8.092752363 ×10 to the power of 22

4 0

3 years ago

Read 2 more answers