All categories

3 years ago

What is one chemical reaction that begins with petroleum as a starting material

Chemistry

1 answer:

emmasim [6.3K]3 years ago

6 0

Answer:

Thermal decomposition or cracking

Explanation:

Petroleum is a mixture of hydrocarbons which are usually formed naturally. Petroleum undergo a host of chemical reactions. One of such is thermal decomposition or cracking.

Cracking is used in the petroleum industry to covert heavy fractions to more useful lighter ones.

When petroleum is subjected to high temperature and pressure, and in the presence of catalyst, the long chain type of petroleum will decompose into more useful smaller and lighter molecules.

Example is given below:

C₁₅H₃₂ → C₈H₁₈ + C₃H₆ + 2C₂H₄

You might be interested in

What phase change is endothermic

LenKa [72]

Sublimation is endothermic

5 0

3 years ago

Read 2 more answers

What process would farmers use to produce vegetables that will grow in a specific climate?

netineya [11]

They would make sure it gets lots of water and it needs sunlight to so some kind of source that could replace the sun

4 0

3 years ago

Sodium has the atomic number 11. How many electrons are in a sodium ion, which has the symbol Na=?

Snezhnost [94]

I believe the answer you're looking for is 10

5 0

3 years ago

Which is not a characteristic of a compound?

shusha [124]

The second answer is not a characteristic because compounds don’t vary from sample to sample. For example NaCl (table salt) is indistinguishable from sample to sample.

4 0

2 years ago

A sample of Cd(OH)2 is added to pure water and allowed to come to equilibrium at 25ºC. The concentration of Cd +2 = 1.7 x 10 -5M

Archy [21]

Answer:

$Ksp=2.0x10^{-14}$

Explanation:

Hello there!

In this case, given the solubilization of cadmium (II) hydroxide:

$Cd(OH)_2(s)\rightleftharpoons Cd^{2+}(aq)+2OH^-(aq)$

The solubility product can be set up as follows:

$Ksp=[Cd^{2+}][OH^-]^2$

Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

$Ksp=(1.7x10^{-5})(3.4x10^{-5})^2\\\\Ksp=2.0x10^{-14}$

Regards!

3 0

3 years ago