Given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.
Given the data in the question;
Hubble's constant;
Age of the universe;
We know that, the reciprocal of the Hubble's constant ( ) gives an estimate of the age of the universe ( ). It is expressed as:
Now,
Hubble's constant;
We know that;
so
Therefore;
Now, we input this Hubble's constant value into our equation;
Therefore, given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.
Learn more: brainly.com/question/14019680
Explanation:
<u>Using equations of motion</u> :
(A) we know that,
u = 0
a = 3.7 m/s^2
S = 63
(B)
v = u + at
21.6 = 0 + 3.7 * t
<u>t (time to reach 63 m) = 5.83 seconds</u>
The answer is Activation Energy …………….
Answer:
(ii) The Electric Field reports the Electric Force on a 1C test charge placed at a particular location.
(iii) The Electric Potential reports the Electric Potential energy of a 1C test charge place at a particular location.
(iv) The spatial derivative of the electric potential at a particular location reports the electric field at that location.
ii, iii and iv are true.
Explanation:
Electric force per unit charge is the electric field. It is a vector. E = F/q.
Electric potential is the electric potential energy per unit charge and is a scalar quantity, like the electric potential. V = U/q where U is the electric potential energy and q the charge.
Electric field exists due to a difference of potential, between two different points.E =dV/dx .