A car moves in a straight line such that for a
1 answer:
Answer:
s = 90 m
a = 56 m/s²
Explanation:
I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t
Position is the integral of differential velocities
s =
s = 3t³ + t² | from 0 to 3
s = 3(3)³ + 3² - (0) = 90 m
acceleration is the derivative of velocity
a = v' = 18t + 2
a(3) = 18(3) + 2 = 56 m/s²
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Answer:
option B
Explanation:
given,
height of building = 0.1 km
ball strikes horizontally to ground at = 65 m
speed at which the ball strike = ?
vertical velocity = 0 m/s
time at which the ball strike
t = 4.53 s
vertical velocity at the time 4.53 s = g × t = 9.8 × 4.53 = 44.39 m/s
horizontal velocity = =14.35 m/s
speed of the ball =
= 46.65 m/s
hence, the speed of the ball just before it strike the ground = 47 m/s
The correct answer is option B