Answer:
s = 90 m
a = 56 m/s²
Explanation:
I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t
Position is the integral of differential velocities
s =
s = 3t³ + t² | from 0 to 3
s = 3(3)³ + 3² - (0) = 90 m
acceleration is the derivative of velocity
a = v' = 18t + 2
a(3) = 18(3) + 2 = 56 m/s²
Answer:
Speed of the runner during video interval is 6.49 m/s
Explanation:
According to the problem,
Number of frames recorded by camera in 1 second = 50
Time takes by camera to record 1 frame = (1/50) s
Time taken by camera to record 77 frames, t = s
Distance covered by the runner during the video recording, d = 10 m
Speed, v =
Substitute the values of d and t in the above equation.
v =
v = 6.49 m/s
Answer:
Acceleration = 1.33m/s² East
Explanation:
Given the following data;
Initial velocity = 10m/s
Final velocity = 50m/s
Time = 30secs
To find the acceleration;
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
Where,
a is acceleration measured in
v and u is final and initial velocity respectively, measured in
t is time measured in seconds.
Substituting into the equation, we have;
Acceleration = 1.33m/s² East