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4 years ago

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Chemistry

1 answer:

Fittoniya [83]4 years ago

8 0

Answer:

The diagram on the right. It has increments of 0.1 of a unit and therefore will provide a more precise measurement. The diagram on the right measures 88.4. In terms of the diagram on the left, a decimal answer cannot be determined because the increments are too large. Therefore the diagram on the left is less precise.

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Help me with questions 1-8. here's the link to the textbook

Ede4ka [16]

Answer:

7 gmkrjfjrjgfhgh

Explanation:

bc I'm dum

6 0

3 years ago

PLEASE HELP ME!!!! WILL GIVE BRAINLIEST!!!!

vitfil [10]

Answer: 1. 3.23 m

2. 32.4

3. B adding solvent and C removing solute

Explanation:

1. Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent

$Molality=\frac{n}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent

Now put all the given values in the formula of molality, we get

$Molality=\frac{43.6mol}{13.5kg}=3.23mol/kg$

2. Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

$3.4=\frac{n}{9.54}$

$n=32.4$

Therefore, the moles of $Na_2CO_3$ is 32.4

3. Molarity can be decreased by decreasing the moles of solute and by increasing the volume of solution.

Thus adding solvent and removing solute will decrease the molarity.

4 0

3 years ago

12.5 mL of 6.0 M KCl is diluted to make a 1.5 L solution. The molarity of the dilution solution is ___ M. (Round atomic masses t

horsena [70]

The molarity of the dilution solution is 0.050 M

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

Dilution formula :

$\tt M_1.V_1=M_2.V_2$

M₁=6 M

V₁=12.5 ml

V₂=1.5 L=1500 ml

$\tt 6\times 12.5=M_2\times 1500\\\\M_2=\dfrac{6\times 12.5}{1500}=0.05~M\\\\for~sig.fig\rightarrow 0.050~M$

4 0

3 years ago

Given the pH of 7. Explain how many hydroxide ions (-OH) and hydronium ions (H30+) are present in the solution.

irga5000 [103]

If the pH is 7, the solution is neutral, which means that it is an equal amount of acid and base.

6 0

3 years ago

Calculate the pH of the solution formed when 45.0 mL of 0.100M NaOH solution is added to 50.0 mL of 0.100M CH3COOH (Ka for aceti

pav-90 [236]

Answer:

pH of soltion will be 5.69

Explanation:

The pH of the solution will be due to excessive acid left and the salt formed. Thus, it will form a buffer solution.

The pH of buffer solution is calculated from Henderson Hassalbalch's equation, which is:

$pH=pKa+log(\frac{[salt]}{[acid]} )$

$pKa=-log(Ka)$

$pKa=-log(1.8X10^{-5})=4.74$

The moles of acid taken :

$moles=molarityXvolume=0.1X50=5mmol$

The moles of base taken:

$moles=molarityXvolume=0.1X45=4.5mmol$

The moles of acid left after reaction :

$5-4.5=05mmol$

The moles of salt formed = 4.5mmol

Putting values in equation

$pH=pKa+log(\frac{[salt]}{[acid]} )=4.74+log(\frac{4.5}{0.5})=5.69$

8 0

3 years ago