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NNADVOKAT [17]
3 years ago
6

Why did the model spacecraft go so much faster than expected on Wednesday?

Physics
1 answer:
Andrew [12]3 years ago
6 0

Answer:

The Wednesday test launch stored more potential energy, and launched the spacecraft at a faster speed because the stronger magnetic field closer to the magnet resulted in a greater increase in potential energy.

Explanation:

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If you wanted to increase your muscular endurance, it would be important to participate in activities that __________.
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In order to increase muscular endurance, it is important to take part in activities that increase the size of muscle cells and the amount of blood that is delivered to the cells<span>. The increased size of the muscle cells reuires them to contract less to accomplish the same task; moreover, the increased blood flow helps deliver oxygen and nutrients to the blood.</span>
3 0
3 years ago
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The pitch of a sound wave is its _________. <br> A.speed B.amplitude C.frequency D.wavelength
Artyom0805 [142]
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Your answer is C. frequency


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8 0
3 years ago
While flying at an altitude of 5.75 km, you look out the window at various objects on the ground. If your ability to distinguish
Bingel [31]

Answer:

the smallest separation between two objects is 0.8067 m

Explanation:

Given the data in the question;

Altitude h = 5.75 km = 5750 m

Diameter D = 4.0 mm = 0.004 m

λ = 460 nm = 4.6 × 10⁻⁷ m

Now, Using Rayleigh criterion for Airy disks resolution.

we know that, Minimum angular separation for resolving two points is;

θ = 1.22λ / D

so we substitute

θ = (1.22 × 4.6 × 10⁻⁷)  / 0.004

θ = 5.612 × 10⁻⁷ / 0.004

θ = 1.403 × 10⁻⁴ rad  

so minimum separation d_{min =  θh

so we substitute

d_{min = (1.403 × 10⁻⁴) × 5750 m

d_{min = 0.8067 m

Therefore, the smallest separation between two objects is 0.8067 m

6 0
3 years ago
a 10-N force is exerted on a box, moving it 20 m in the same direction. What is the magnitude of work done on the box?
-Dominant- [34]
F = 10 N

d = 20 m

θ = 0°

W = F (dot product) D = F * D * cos(angle between them)

W = FDcosθ

W = 10 * 20 * cos0 = 200 J
8 0
3 years ago
When a gear rotates 20 revolutions, it achieves an angular velocity of 30 rad/s, starting from rest. determine its constant angu
Temka [501]
Initial angular velocity  = 0  (starting from rest)
Final angular velocity = 30 rad/s
Distance traveled = (20 rev)*(2π rad/rev) = 40π rad

Let the angular acceleration be α rad/s².
Then
(30 rad/s)² = (0 rad/s)² + 2*(α rad/s²)*(40π rad)
α = 3.58 rad/s²

Answer: 3.58 rad/s² (nearest hundredth)
4 0
4 years ago
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