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3 years ago

in the image, balls that look alike represent the same atom. based on this information, what do the images below represent

Physics

2 answers:

mart [117]3 years ago

8 0

Answer:

molecules of elements

Explanation:

An element is formed of one type of atoms. An element is a pure substance. A compound is formed of atoms of different elements chemically combined together in fixed ratio. A molecule of compound has different type of atoms chemically combined. For example, a water molecule is of compound having 2 hydrogen atoms and 1 oxygen atom. A molecule of element has same type of atoms chemically combined. For example oxygen O₂ is a molecule of element.

In the given diagram, same atoms are chemically combined. Thus, these represent molecules of elements.

scoundrel [369]3 years ago

3 0

Answer:

molecules of elements

Explanation:

An element is formed of one type of atoms. An element is a pure substance. A compound is formed of atoms of different elements chemically combined together in fixed ratio. A molecule of compound has different type of atoms chemically combined. For example, a water molecule is of compound having 2 hydrogen atoms and 1 oxygen atom. A molecule of element has same type of atoms chemically combined. For example oxygen O₂ is a molecule of element.

In the given diagram, same atoms are chemically combined. Thus, these represent molecules of elements.

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3 years ago

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Two 10-cm-diameter metal plates 1.0 cm apart are charged to {12.5 nC. They are suddenly connected together by a 0.224-mm- diamet

Alekssandra [29.7K]

Answer:

(a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Explanation:

Given that,

Diameter of metal plates = 10 cm

Distance between the plates = 1.0 cm

Charged = 12.5 nC

Diameter of copper wire = 0.224 mm

We need to calculate the cross section area of the plates

Using formula of area

$A=\pi r^2$

Put the value into the formula

$A=\pi\times(5\times10^{-2})^2$

$A=7.85\times10^{-3}\ m^2$

We need to calculate the capacitor

Using formula of capacitor

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.85\times10^{-3}}{1.0\times10^{-2}}$

$C=6.94\times10^{-12}\ F$

We need to calculate the resistance of the wire

Using formula of resistivity

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{1.7\times10^{-8}\times1.0\times10^{-2}}{\pi\times(0.1125\times10^{-3})^2}$

$R=4.27\times10^{-3}\ \Omega$

We need to calculate the voltage

Using formula of charge

$q=CV$

$V=\dfrac{q}{C}$

Put the value into the formula

$V=\dfrac{12.5\times10^{-9}}{6.94\times10^{-12}}$

$V=1.801\times10^{3}\ V$

(a). We need to calculate the current

Using formula of current

$I=\dfrac{V}{R}$

$I=\dfrac{1.801\times10^{3}}{4.27\times10^{-3}}$

$I=421779.85\ A$

$I=4.217\times10^{5}\ A$

(b). We need to calculate the electric field

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times12.5\times10^{-9}}{(1.0\times10^{-2})^2}$

$E=11.2\times10^{5}\ N/C$

The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c). In this case, the voltage between the capacitor plates decreases as the charge decreases with time.

The current is directly proportional to the voltage between the plates .

Hence, The current also decrease with time.

(d). We need to calculate the total amount of energy dissipated in the wire

Using formula of energy

$E=\dfrac{1}{2}CV^2$

Put the value into the formula

$E=\dfrac{1}{2}\times6.94\times10^{-12}\times(1.801\times10^{3})^2$

$E=1.126\times10^{-5}\ J$

The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Hence, (a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

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3 years ago

What is pin hole camera?

lesya692 [45]

Answer:

Explanation:

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4 years ago

Which statement best describes the process that produced the ending populations of moths

zzz [600]

C. Light color became an adaptation in the surviving moths? Not fully sure.

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4 years ago

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a car with an initial velocity of 10ms north was accelerated for 6 second until it ha a final velocity of 25ms north, what is th

koban [17]

Answer:

2 1/2 m/s^2 or 2.5m/s^2

Explanation:

From the question

final velocity v =25m/s

Initial velocity u =10m/s

time = 6 seconds

acceleration a = ?

Using the equation for linear motion

v = u + at

25 = 10 + a x 6

25 = 10 + a6

Subtract 10 from both sides

25-10 = 10 + a6 -10

25 - 10 = 10 -10 + a6

15 = a6

Divide both sides by 6

15/6 = a6/6

5/2 = a

a = 2 1/2 m/s^2 or 2.5m/s^2

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3 years ago

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