Answer:
The answer is 3
C2H5OH + O2 CO2 +H2O (unbalanced)
C2H5OH +3O2(g). 2CO2(g)+3H2O(balanced)
1 mole of water = 18 grams (you can find this by finding mass of two hydrogen and one oxygen which is (1*2) + 16 = 18)
1.8 grams = 0.1 moles
1 H2O molecule has 10 electrons so 0.1 moles can be computed as:
(6.023*10^23)*(0.1)*10 = 6.023*10^23 electrons
