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PtichkaEL [24]
4 years ago
15

What is the the electron configuration for the element ge. use the noble gas preceding for the inner electron?

Chemistry
1 answer:
Vlad1618 [11]4 years ago
3 0
[Ar] 3d^10 4s^2 4p^2
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The ka of hf is 6.8 x 10-4. what is the ph of a 0.35 m solution of hf?
damaskus [11]
When the reaction equation is:

HF ↔ H+   +   F-

and when the Ka expression
= concentration of products/concentration of reactions

so, Ka = [H+][F-]/[HF]

when we assume:

[H+] = [F-] = X

and [HF] = 0.35 - X

So, by substitution:

6.8 x 10^-4 = X^2 / (0.35 - X) by solving for X

∴ X = 0.015 M

∴[H+] = X = 0.015

when PH = -㏒[H+]

∴PH = -㏒0.015

        = 1.8
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