Answer: The correct answer is -297 kJ.
Explanation:
To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:
2SO3 —> O2 + 2SO2 (196 kJ)
Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.
Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:
SO3 —>1/2O2 + SO2 (98 kJ)
S + 3/2O2 —> SO3 (-395 kJ)
Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.
S + O2 —> SO2
Now, we must add the enthalpies together to get our final answer.
-395 kJ + 98 kJ = -297 kJ
Hope this helps!
There is 1 H atom: (1)(+1) = +1 The oxidation number of O is -2. There are 4 O atoms here: (4)(-2) = -8 So the oxidation state of Cl is +7.
NOTE: The maximum positive oxidation number for chlorine is +7,<span> the same as its group number (VII).</span>
Answer:150g of gold
Explanation: There is a lot more gold and gold is significantly significantly more dense than lithium
Explanation:
Carbon monoxide and hydrogen gas reacts together to form methanol:
CO + 2H2 => CH3OH
Since 0.266mol * 2 = 0.532mol > 0.524mol, the limiting reactant here is hydrogen and therefore there will be 0.524mol / 2 = 0.262mol of methanol.
sodium chloride is a compound that is stable because its constituent elements namely chlorine and sodium have formed ionic bonds with each other and their outer energy shells are filled with 8 electrons.
Sodium on its own has 11 electrons. Two of these are in the 1st energy level, eight in the 2nd energy level and one in the 3rd energy level. This arrangement is highly unstable rendering the element sodium highly unstable and reactive. It will burst into flames immediately on exposure to air and can burn through human flesh if it comes into contact with it.
Chlorine at room temperature is a poisonous gas. It has 17 electrons in the arrangement 2:8:7 . The outermost shell has 7 electrons and so this element is fairly stable but will readily react with human lungs with fatal consequences.
So each of these two elements on their own are deadly, but when the two react together, sodium gives up its single electron on the outer energy shell to chlorine which readily accepts it and fills its outer shell to make 8 forming ionic bonds and is thus the two are completely stable and cannot explode or react in any other way because the outer shell of each of them is now filled with 8 electrons.
