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3 years ago

What is the role of neutrons in an atom??

2 answers:

Colt1911 [192]3 years ago

7 0

They're only found in the nucleus and play an important role in keeping the atom stable because they carry a negative charge to counteract the proton's positive charge.

daser333 [38]3 years ago

4 0

Neutrons are found only in the nucleus of the atom, where they play an important role in keeping the atom stable. Since protons are positively charged, there is an incredibly strong repulsive force between all the protons in a nucleus.

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How many MOLECULES are in 50.0 grams of lithium phosphate?

Ray Of Light [21]

Answer: 2.60 x 10^23 molecules

50.0 grams x (1 mol/115.79 grams) = 0.431816219 moles

0.431816219 mol x (6.02 x 10^23 molecules/1 mol) = 2.599533638 x 10^23 molecules (final answer is rounded)

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3 years ago

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slavikrds [6]

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3 years ago

How an ionic compound made up of charged particles can be electrically neutral

finlep [7]

Answer:

Explanation:

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3 years ago

Given the balanced equation below, how many moles of chromium are

fenix001 [56]

Bbbbbbbbbbbbbbbbbbbbbbbb

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3 years ago

A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________

gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

Average velocities of gases can be expressed as root-mean-square averages. (V rms)

$\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}$

R = gas constant, T = temperature, Mm = molar mass of the gas particles

From the question

R = 8,314 J / mol K

T = temperature

Mm = molar mass, kg / mol

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

$\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s$

b. the effusion rates of two gases = the square root of the inverse of their molar masses:

$\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }$

M₁ = molar mass sulfur dioxide = 64

M₂ = molar mass nitrogen triodide = 395

$\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5$

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

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3 years ago