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Sidana [21]
3 years ago
12

The sun, on average is 93 million miles frome earth. How many meters is this?

Physics
2 answers:
Drupady [299]3 years ago
6 0
The answer is 149668992000 meters.
Katyanochek1 [597]3 years ago
3 0
Hello there,
93 miles = 149669 meters

Hope this helps :))

~Top
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A woman starts to swim directly across a 5.2-km-wide river. Her speed with respect to the water is 1.9 m/s. The river current ca
elena-14-01-66 [18.8K]

Answer:

(a) the time needs for her to cross the river is 2736.8 s.

(b) the distance takes to reach the other side of the river is 2490.5 m.

Explanation:

given information:

woman's speed, v₁ = 1.9 m/s

the wide of river, s = 5.2 km = 5200 m

river's current, v₂ = 0.91 m/s

(a) How much time does it take her to cross the river?

s = v t

s = the displacement (m)

v = speed (m/s)

t = time (s)

s = v t

t = s/v

 = 5200/1.9

 = 2736.8 s

(b) How far downstream will the river carry her by the time she reaches the other side of the river?

s = v t

  = (0.91) (2736.8)

  = 2490.5 m

8 0
3 years ago
What do we call the days when the sun is directly overhead the equator?
NikAS [45]

Answer:

Equinox

Explanation:

It is an astronomical phenomenon that is repeated twice a year, in summer and winter, and that is caused because the axis on which our planet rotates is slightly inclined with respect to the plane of translation, this is its trajectory around the Sun.

For this reason there are two equinoxes a year, a phenomenon completely opposite to the solstice, but also marks the beginning of the spring and autumn seasons.

The equinoxes occur around March 20 or 21 and September 22 or 23, and it is the days when the Sun is exactly over the equator, which makes day and night more or less the same duration. The word ‘equinox’ comes from Latin and means precisely ‘same night’. In those two moments the part of the Earth closest to the Sun is the equator.

8 0
3 years ago
A particle moving in simple harmonic motion with a period T = 1.5 s passes through the equilibrium point at time t0 = 0 with a v
ch4aika [34]

Answer

given,

Time period= T = 1.5 s

If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s

v_max=1.00 m/s

we know,

v_ max=A ω  

v = A sin (ωt)

-0.50= -1.00 sin (ωt)

sin (ωt)  =  0.5

\omega t = sin^{-1}(0.5)

\dfrac{2\pi}{T}\times t =0.524

\dfrac{2\pi}{1.5}\times t =0.524

t = 0.125 s

we have time period T=1.5 it is the time to complete one oscillation

means from eq to right,then left,then eq,then left,then from right to eq

time taken for left = t/4 = 0.125/4 = 0.375 s

smallest value of time

=0.375 + 0.125

= 0.50 sec

7 0
3 years ago
150kg object takes 1.5minutes to travel 2,500 meter straight path it begins the trip traveling 120m/s and decelerates to a veloc
Free_Kalibri [48]
<h2>Answer:</h2>

Acceleration= -1.11 m/sec²


<h2>Explanation:</h2>

Date Given to us is

Mass = 150 kg

Time = 1.5 minutes = 90 seconds

Distance = 2500 meters

Initial Velocity = 120 m/s

Final Velocity = 20 m/s

Acceleration = ?

<u>Solution:</u>

By using First Equation of motion

Vf = Vi + at

Putting the values

20 = 120 + a (90)

Subtracting 120 on both sides

20-120 = 120 + a(90) - 120

-100 = 90 a

Dividing both sides by 90

-100/90 = 90 a / 90

-1.11 = a

So the acceleration is -1.11 m/s²

3 0
4 years ago
Suppose you lived in the crater copernicus on the side of the moon facing the earth. during what fraction of the time would you
Nat2105 [25]

The phase of the moon facing the Earth is always the same, which means that the speed of rotation of the moon and the Earth are the same. Because of which the other part of the moon is not visible to the people on Earth.
6 0
4 years ago
Read 2 more answers
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