Explanation:
Red dwarf and brown dwarf masses are less than a typical white dwarf mass measuring around 1.2 solar masses. But it's only a few kilometers of the radius. This is precisely because there is no force to overcome the contraction due to gravity. There is a constant battle between the external force of fusion (who wants to expand the star) and inward pressure because of gravity (who wants to compact the star) of regular stars on the main sequence. There remains a balance between these two forces as long as the star remains on the celestial equator.
Red dwarfs are helped by the nuclear fusion force, but brown dwarfs were not large enough to cause the fusion of hydrogen, they are massive enough to generate sufficient energy in the core by fusing deuterium to sustain their volume. However as soon as the star runs out of hydrogen to burn it weakens the force of the external fusion and gravity starts to compact the center of the star. The contraction heats up the core into more massive stars and helium fusion begins, rendering the star once again stable. However this helium fusion does not occur in stars with masses below 1.44Mo. Tightness persists for such stars until the star's gasses degenerate.
Answer:
198.9 Nm
Explanation:
Torque = Force * Rperpendicular, since the force applied is 39, and the radius is 5.1, we can build an equation that will lead to 198.9=39*5.1.
Answer:
Explanation:
Given data
Linear speed of spaceship V=39000 km/h =10833.3 m/s
The radius of circular motion r=4360 km=4360000 m
For Part (a) angular velocity
The angular velocity is given by:
Substitute the given values
So
For Part(b) The radial acceleration of spaceship
The radial acceleration is given by:
Substitute given values and value of ω
So
For Part (c) The tangential acceleration
The spaceship is rotating with constant angular velocity,then the tangential acceleration of spaceship is zero
So
Answer:
human body contain 80% water and water is a good condition of current because our body fluid contain different type of salt that increase the current conductivity
