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oee [108]
3 years ago
10

A 0.150 kg baseball is thrown upward with an initial speed of 20.0 m/s. what is the force on the ball when it reaches half of it

s maximum height
Physics
1 answer:
dybincka [34]3 years ago
3 0
Since we are ignoring air resistance, the only force acting on the ball will be the force of gravity.

According to Newton's second law:
F = ma where:
m is the mass of the ball = 0.15 kg
a is acceleration due to gravity = 9.8 m/sec^2

Substitute to get the force as follows:
Force = 0.15 * 9.8 = 1.47 Newton
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See the answers below

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F =G*\frac{m_{1}*m_{2}}{r^{2} }

where:

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The value is   t =  14.129 \  minutes    

Explanation:

From the question we are told that

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   =>     t =  14.129 \  minutes    

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