The work done on the box by the applied force is zero.
The work done by the force of gravity is 75.95 J
The work done on the box by the normal force is 75.95 J.
<h3>The given parameters:</h3>
- Mass of the box, m = 3.1 kg
- Distance moved by the box, d = 2.5 m
- Coefficient of friction, = 0.35
- Inclination of the force, θ = 30⁰
<h3>What is work - done?</h3>
- Work is said to be done when the applied force moves an object to a certain distance
The work done on the box by the applied force is calculated as;

where;
a is the acceleration of the box
The acceleration of the box is zero since the box moved at a constant speed.

The work done by the force of gravity is calculated as follows;

The work done on the box by the normal force is calculated as follows;

Learn more about work done here: brainly.com/question/8119756
Answer:
Current is in phase with voltage in a resistive circuit. Note that the wave form for power is always positive, never negative for this resistive circuit. This means that power is always being dissipated by the resistive load, and never returned to the source as it is with reactive loads.Explanation:
If the car travels
300 km.........................5 hrs
?km ..............................2h
to find out we do (300*2)/5=600/5=120km
also
300km/5h=60km/h
in 2 hours
120km
Answer: W = 11340J
Explanation:
Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.
So this is the Formula: Power = Work / Time.
<u>Step 1:</u><em><u> Find the Formula</u></em>
P = W / T
<em><u>
</u></em>
<u>Step 2: </u><u><em>Make W the subject of the equation.</em></u>
W = PT
<u>Step 3:</u><u> </u><u><em>Given.</em></u>
P = 270 Watts, T = 42 seconds
<u>Step 4:</u><u><em> Substitute these values into equation 2
.</em></u>
W = 270(42)
<u>Step 5:</u><u> </u><u><em>Simplify.</em></u>
W = 11340J
The amount of work done was 11340.
~I hope I helped you! :)~
The final velocity is +15.0 m/s
Explanation:
The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:

where
v is the velocity at time t
u is the initial velocity
a is the acceleration
t is the time
For the cart in this problem, we have:
u = +3.0 m/s (initial velocity)
(acceleration)
t = 8.0 s (time)
Substituting, we find the final velocity:

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