Answer:
80.16 m/s^2
at t=2 s
x=42.3 m
y=16 m
z=14 m
Explanation:
solution
The x,y,z components of the velocity are donated by the i,j,k vectors.

acceleration is a derivative of velocity with respect to time.
![a_{x}=\frac{d}{dt} v_{x}=\frac{d}{dt}[16t^{2}]=32t\\a_{y}=\frac{d}{dt} v_{y}=\frac{d}{dt}[4t^{3}]=12t^{2} \\a_{z}=\frac{d}{dt} v_{z}=\frac{d}{dt}[5t+2]=5](https://tex.z-dn.net/?f=a_%7Bx%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7Bx%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B16t%5E%7B2%7D%5D%3D32t%5C%5Ca_%7By%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7By%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B4t%5E%7B3%7D%5D%3D12t%5E%7B2%7D%20%5C%5Ca_%7Bz%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7Bz%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B5t%2B2%5D%3D5)
evaluate acceleration at 2 seconds

the magnitude of the acceleration is the square root of the sum of the square of each component of the acceleration.

position is the integral of velocity with respect to time position at a time can be found by taking by taking the definite intergral of each component.

Answer:
Technician A
Explanation:
Ohms law: I= E/R so rest resistance must be present along with E/potential difference. Even if just wire shorted together there is resistance but very little.
Tech B: Again ohms law. Current flow is directly proportional to the voltage and inversely proportional to R (resistance or impedance).
Answer:
The speed of shaft is 1891.62 RPM.
Explanation:
given that
Amplitude A= 0.15 mm
Acceleration = 0.6 g
So
we can say that acceleration= 0.6 x 9.81

We know that

So now by putting the values



We know that
ω= 2πN/60
198.0=2πN/60
N=1891.62 RPM
So the speed of shaft is 1891.62 RPM.
Answer:
See explanation
Explanation:
Solution:-
- The shell and tube heat exchanger are designated by the order of tube and shell passes.
- A single tube pass: The fluid enters from inlet, exchange of heat, the fluid exits.
- A multiple tube pass: The fluid enters from inlet, exchange of heat, U bend of the fluid, exchange of heat, .... ( nth order of pass ), and then exits.
- By increasing the number of passes we have increased the "retention time" of a specific volume of tube fluid; hence, providing sufficient time for the fluid to exchange heat with the shell fluid.
- By making more U-turns we are allowing greater length for the fluid flow to develop with " constriction and turns " into turbulence. This turbulence usually at the final passes allows mixing of fluid and increases the heat transfer coefficient by:
U ∝ v^( 0.8 ) .... ( turbulence )
- The higher the velocity of the fluids the greater the heat transfer coefficient. The increase in the heat transfer coefficient will allow less heat energy carried by either of the fluids to be wasted ; hence, reduced losses.
Thereby, increases the thermal efficiency of the heat exchanger ( higher NTU units ).
Answer:
1. Can you tell me something about yourself?
2. What are you weaknesses?
3. If you would describe yourself in one word?
Explanation: Those questions above 1, 2, and 3 are not harmful to ask your client. Bit the last two 4 and 5 are very harmful, because you don't need to be all up in they business and you don't want to put a lot of pressure on your client.
Hope this helps☝️☝☝