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KiRa [710]
3 years ago
11

What is a jack plane used for​

Engineering
1 answer:
kolezko [41]3 years ago
4 0

A jack plane is a general purpose woodworking bench plane, used for dressing timber down to the correct size in preparation for truing and/or edge jointing.

I hope this helps you :)

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You are about to perform PMCS on your M1114? What resource should you use for the procedures and instructions for performing PMC
aniked [119]

The resources and instructions that should be used for the procedures of performing PMCS are:

  1. Operator's manuals
  2. Safety cautions and warnings.
  3. Fording kit
  4. Heating and cooling systems.

<h3>What is PMCS?</h3>

PMCS is an acronym for preventive maintenance checks and services and it can be defined as the maintenance, checks, and services that are typically performed before, during, and after the use of any type of military equipment such as:

  • M1114
  • M1151
  • M1123

Basically, the resources and instructions that should be used for the procedures of performing PMCS are:

  1. Operator's manuals
  2. Safety cautions and warnings.
  3. Fording kit
  4. Heating and cooling systems.

Read more on PMCS here: brainly.com/question/15720250

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2 years ago
HAPPINESS DISCUSSION
RideAnS [48]

Answer:

uh because life sucks o_<

8 0
3 years ago
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Engineering is the use of scientific principles to design and build machines, structures, and other items, including bridges, tu
Thepotemich [5.8K]

Is this a question or a statement?

4 0
3 years ago
A very long pipe of 0.05 m (r1) radius and 0.03 m thickness (r2 - r1) is buried at a depth of 2m (z) to transport liquid nitroge
Elenna [48]

Answer:

The surface temperature of the ground is = 296.946K

Explanation:

Solution

Given

r₁= 0.05m

r₂= 0.08m

Tn =Ti = 77K

Ki = 0.0035 Wm-1K-1

Kg =  1 Wm-1K-1

Z= 2m

Now,

The outer type temperature (Skin temperature pipe)

Q = T₀ -T₁/ln (r2/r1)/2πKi = 2πKi  T0 -T1/ln (r2/r1)

Thus,

10 w/m = 2π * 0.0035 = T0 -77/ln 0.08/0.05

⇒ T₀ -77 = 231.72

    T₀= 290.72K

The shape factor between the cylinder and he ground

S = 2πL/ln 4z/D

where L = length of pipe

D = outer layer of pipe

S = 2π * 1/4 *2/ 2 * 0.08 = 1.606m

The heat gained in the pipe is = S  * Kg * (Tg- T₀)

(10* 1) = 1.606 * 1* (Tg- 290.72)

Tg - 290.72 = 6.2266

Tg = 296.946K

Therefore the surface temperature to the ground is 296.946K

6 0
3 years ago
How is the angle between power strokes determined?
aivan3 [116]
And there's an equation to help determine which configurations will work best. In a four-stroke engine, an individual piston fires every 720 degrees (two crankshaft rotations). ... The flat-four fires at 180-degree intervals, and its V angle is 180 degrees, which leads to a balance of firing forces.Jan 14, 2011

I’m not for sure if this is what you we’re looking for
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