To solve this problem we will apply the concepts related to wavelength, as well as Rayleigh's Criterion or Optical resolution, the optical limit due to diffraction can be calculated empirically from the following relationship,

Here,
= Wavelength
d= Diameter of aperture
= Angular resolution or diffraction angle
Our values are given as,

The frequency of the sound is 
The speed of the sound is 
The wavelength of the sound is

Here,
v = Velocity of the wave
f = Frequency
Replacing,


The diffraction condition is then,

Replacing,

d = 0.24 m
Therefore the diameter should be 0.24m
If the machine's mechanical advantage is 4.5, that means that
Output force = (4.5) x (Input force) .
We know the input force, and we need to find the output force. Rather than wander around the room looking at the floor while our hair smolders, let's try putting the numbers we know into the equation I wrote up there. OK ?
Output force = (4.5) x (Input force)
Output force = (4.5) x (800 N)
Now dooda multiplication:
<em>Output force = 3,600 N</em> .
That's exactly what the question asked for. So we're done !
The electrostatic force is directly proportional to the product of the charges, by Coulomb's law.
F α Qq
If the charges are now half the initial charges:
<span>F α (1/2)Q *(1/2)q
</span>
F α (1/4)Q<span>q
The new force when the charges are each halved is (1/4) the first initial force experienced at full charge.</span>
Answer:
2400 J
Explanation:
Latent heat: This is also called hidden heat, it is the heat that is not detectable by the thermometer.
From the question,
Q = cm.................. Equation 1
Where Q = Energy, c = specific latent heat of the liquid, m = mass of the liquid.
Given: c = 4000 J/kg, m = 600 g =( 600/1000) kg = 0.6 kg
Substitute these values into equation 1
Q = 4000×0.6
Q = 2400 J
Hence the energy required is 2400 J
Answer:
20meters per second
Explanation:
2000meters/50seconds= 20m/s