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3 years ago

A 12V battery runs a 30 amp car stereo. What is the resistance of the circuit?

1 answer:

6 0

So to find R (resistance) you do ohm's law E (volts) over I (current) to find R
So this is 12/30 = 0.4 so the resistance is 0.4

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A diver is swimming underneath an oil slick with a thickness of 200 nm and an index of refraction of 1.50. A white light shines

Tcecarenko [31]

Answer:

Explanation:

thickness of oil t = 200 nm

index of refraction μ = 1.5

For transmitted light :---

path difference = 2μ t

For constructive interference

path difference = n λ , λ is wavelength of light

2μ t = n λ

λ = 2μ t / n

For longest λ , n = 1

λ = 2μ t

= 2 x 1.5 x 200 nm

= 600 nm

Wavelength in water

= 600 / refractive index of water

= 600 / 1.33

= 451.1 nm Ans

4 0

4 years ago

A ski lift carries a 75.0-kg skier at 3.00 m/s for 1.50 min along a cable that is inclined at an angle of 40.0° above the horizo

Nookie1986 [14]

Answer

given,

mass of the ski = 75 Kg

speed of the skier, v = 3 m/s

time = 1.50 min = 90 s

angle of inclination, θ = 40°

distance = s x t

= 3 x 90 = 270 m

a) W = F. d cos θ

W = mg. d cos θ

W = 75 x 9.8 x 270 x cos 40°

W = 152021.52 J

work is done by the ski lift is equal to 152021.52 J

b) Power extended by the ski

$Power = \dfrac{Work\ done}{time}$

$Power = \dfrac{152021.52}{90}$

P = 1689.13 Watt.

power is expended by the ski lift is equal to 1689.13 W.

3 0

3 years ago

The atomic number tells how many _____ are in the nucleus

maria [59]

Answer:

1 because I looked it up for sure

4 0

3 years ago

How do leptons differ from hadrons?

Savatey [412]

I'll just give you the link for it but count it as my answer. http://www.differencebetween.com/difference-between-leptons-and-vs-hadrons/

4 0

4 years ago

A baseball player friend of yours wants to determine his pitching speed. You have him stand on a ledge and throw the ball horizo

Alla [95]

Answer:

$v_{ox}= 19.6\ m/s$

Explanation:

Data provided in the question:

Height above the ground, H= 5.0m

Range of the ball, R= 20 m

Initial horizontal velocity = $v_{ox}$

Initial vertical velocity= $v_{oy}$ (Since ball was thrown horizontally only)

Acceleration acting horizontally, $a_x$ = 0 m/s² [ Since no acceleration acts horizontally) ]

Vertical Acceleration, $a_y$ = 9.8 m/s² (Since only gravity acts on it)

Let 't' be the time taken to reach ground

Therefore, using equations of motion, we have

$H= v_{oy}t+\frac{1}{2}a_yt^2$

$5= (0)t+\frac{1}{2}(9.8)t^2$

$t= \frac{10}{9.8}=1.02 s$

Then using Equations of motion for horizontal motion,

$R= v_{ox}t+\frac{1}{2}a_xt^2$

$20= v_{ox}(1.02)+\frac{1}{2}(0)(1.02)^2$

$v_{ox}= 19.6\ m/s$

4 0

3 years ago