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3 years ago

9

Plz help with this!

2 answers:

Ksenya-84 [330]3 years ago

4 0

Answer:

An external force acting on the object.

Explanation:

According to Newton's first law, objects remain in uniform motion in a straight line, or rest, unless <em>acted upon by an external force</em>.

An object slowing down experiences deceleration (or, negative acceleration). Acceleration (positive or negative) implies action of an external force.

One example of an external force causing an object to slow down can be a force of friction, however, there can be many other sources of force achieving the same effect (including simply your hand pushing against it).

salantis [7]3 years ago

3 0

The Answer is Friction

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Read 2 more answers

A series RLC circuit with R = 15.0 ohms, C = 4.70 uF, and L = 25.0mH is connected to an AC voltage source with V(t) = 75.0 Vrms

Brilliant_brown [7]

(a) The rms current in the circuit is 2.58 A.

(b) The rms voltage of Vab is 38.7 V, Vbc is 158.83 V, Vcd is 222.93 V, Vbd is 64.11 V, and Vad is 75 V.

(c) The average rate at which energy is dissipated in each of the 3 circuit elements is 193.23 W.

<h3>Capacitive reactance of the circuit</h3>

The capacitive reactance of the circuit is calculated as follows;

$X_c = \frac{1}{\omega C} = \frac{1}{2\pi fC} = \frac{1}{2\pi \times 550 \times 4.7 \times 10^{-6}} \\\\X_c = 61.56 \ ohms$

<h3>Inductive reactance of the circuit</h3>

Xl = ωL

Xl = 2πfL

Xl = 2π x 550 x 25 x 10⁻³

Xl = 86.41 ohms

<h3>Impedance of the circuit</h3>

$Z = \sqrt{R^2 + (X_L - X_C)^2} \\\\Z = \sqrt{15^2 + (86.41 -61.56)^2 } \\\\Z = 29.03 \ ohms$

<h3>rms current in the circuits</h3>

$I_{rms} = \frac{V_{rms}}{Z} \\\\I_{rms} = \frac{75}{29.03} \\\\I_{rms} = 2.58 \ A$

<h3>rms voltage in resistor (Vab)</h3>

$V_{ab} = I_{rms} R\\\\V_{ab} = 2.58 \times 15\\\\V_{ab} = 38.7 \ V$

<h3>rms voltage in capacitor (Vbc)</h3>

$V_{bc} = I_{rms} X_c\\\\V_{bc} = 2.58 \times 61.56\\\\V_{bc} = 158.83 \ V$

<h3>rms voltage in inductor (Vcd)</h3>

$V_{cd} = I_{rms} X_l\\\\V_{cd} = 2.58 \times 86.41\\\\V_{cd} = 222.93\ V$

<h3>rms voltage in capacitor and inductor (Vbd)</h3>

$V_{bd} = I_{rms} \times (X_l - X_c)\\\\V_{bd} = 2.58 \times (86.41 - 61.56)\\\\V_{bd} = 64.11 \ V$

<h3>rms voltage in resistor, capacitor and inductor (Vad)</h3>

$V_{ad} = I_{rms} \times \sqrt{R^2 + (X_l- X_c)^2} \\\\V_{ad} = 2.58 \times Z \\\\V_{ad} = 2.58 \times 29.03\\\\V_{ad} = 75 \ V$

<h3>Average rate of energy dissipation in the 3 circuit element</h3>

$P = I_{rms}^2 Z\\\\P = (2.58)^2 \times 29.03\\\\P = 193.23 \ W$

Learn more about RLC series circuit here: brainly.com/question/15595203

6 0

2 years ago

7. Four perpendicular forces, 2 N, 3 N, 9 N and 10 N act on object P as shown in Diagram 2. 10 N A B 9 N 3 N 2 N P Diagram 2 Wha

Anvisha [2.4K]

Answer: R=

A

2

+B

2

+2ABcosθ

θ=90

o

cos90

o

=0

R=

A

2

+B

2

=

3N

2

+4N

2

=5N

Explanation:

6 0

2 years ago