Here, height is given which will be the distance for a freely falling object.
The velocity will be
and the acceleration will be
In this way, the formula works.
If the moon phase is seen as a waxing crescent moon in london, what phase of the moon would be seen in new york if it's viewed a
1 answer:
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Answer: 117 kPa
Explanation:
For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa
For the liquid at depth 9m, the gauge pressure is equal to= P₂
Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.
So, For finding gauge pressure we have formula P= ρ * g * h
Also gravity also remains same for both liquids
So taking ratio of their respective pressures we have
=
So =
Or P₂= 39 * 3 = 117 kPa