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2 years ago

12

Isotopes do not have the same number of which of these?

2 answers:

butalik [34]2 years ago

6 0

Answer is: neutrons.
Isotopes have same number of protons and different number of neutrons. For example hydrogen has three isotopes: protium(one proton, no neutron), deuterijuma (one proton, one neutron), tritiumt(one proton, two neutrons).

Sindrei [870]2 years ago

3 0

Isotopes are basically from the same element. In terms of subatomic particles of the element, the isotopes will then basically have the same number of protons. The electrons also have to be same in number given that the elements are in neutral charges.

We are then left with neutrons, which is one of the subatomic particles residing in the nucleus of an atom.

Thus, the answer is NEUTRONS.

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3 years ago

Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH

Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{12 g}{60 g/mol}$

= 0.2 mol

Molarity of acetic acid is calculated as follows.

Density = $\frac{mass}{volume}$

1 g/ml = $\frac{100 g}{volume}$

volume = 100 ml

Hence, molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{0.2 mol}{0.1 L}$

= 2 mol/l

As reaction equation for the given reaction is as follows.

$NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O$

So, moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

$x \times 1 M = 10 mL \times 2 M$ (as 1 L = 1000 ml)

x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.

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Read 2 more answers

Li + HNO3 > LiNO3 + H2 how do I balance it? Show work pls

azamat

Answer: The balanced equation is $2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$ .

Explanation:

The given reaction equation is as follows.

$Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}$

Number of atoms present on reactant side are as follows.

Li = 1
H = 1
$NO_{3}$ = 1

Number of atoms present on product side are as follows.

Li = 1
H = 2
$NO_{3}$ = 1

To balance this equation, multiply Li by 2 and $HNO_{3}$ by 2 on reactant side. Also, multiply $LiNO_{3}$ by 2 on product side.

Hence, the equation can be rewritten as follows.

$2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$

Now, number of atoms present on reactant side are as follows.

Li = 2
H = 2
$NO_{3}$ = 2

Number of atoms present on product side are as follows.

Li = 2
H = 2
$NO_{3}$ = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is $2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$ .

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2 years ago