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yawa3891 [41]
3 years ago
9

Ashley squirrel, named Jackie, rides on a bicycle with a constant kinetic energy of 3.6J. The mass of combination of Jackie and

the bicycle is 0.65 kg. What is the velocity of the combination of Jackie and the bicycle?
Physics
2 answers:
yKpoI14uk [10]3 years ago
6 0

The velocity of the combination of Jackie and the bicycle is 3.328 m/s.

Explanation:

From the given data the constant kinetic energy is 3.6 J. The mass of combination is 0.65 kg. To find the velocity of the combination of Jackie and the bicycle the formula  is

KE = 0.5 x mv2.

To find velocity,

V2=ke/(0.5×m)

V=\sqrt{(ke/(0.5*m)

v= 3.6/(0.5×0.65)

=\sqrt (11077/10)/10

v= 3.328 m/s

Hence, the velocity of the combination of Jackie and the bicycle is 3.328m/s.

svlad2 [7]3 years ago
4 0

The combined velocity is 3.33 m/s.

Answer:

Explanation:

Kinetic energy is the measure of the energy experienced by moving objects. So the mathematical expression of kinetic energy will be directly proportional to the product of mass and square of the velocity of the object.

As the combined mass of Jackie and bicycle is 0.65 kg and the kinetic energy  is given as 3.6 J. Then the velocity of the combined Jackie and bicycle is

Kinetic energy = 1/2 mv²

v=\sqrt{\frac{2*E}{m} }

v = \sqrt{\frac{2*3.6}{0.65} }=\sqrt{11.08}

So combined velocity is 3.33 m/s.

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A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4
denpristay [2]
Answer= 8m/s

Because total Momentum before= total momentum after

Momentum before (p=mu)
p=(4)(12)= 48
p=2(0)=0
So total momentum before=48

Momentum after (p=mu)
Masses combined —2+4=6kg
p=6u


Mb=Ma
48=6u
u=8m/s
3 0
3 years ago
A plane travelling at 63 m/s[S] down a runway begins accelerating uniformly at 2.8 m/s?[S]. How far does it travel
AVprozaik [17]

Answer:

270 m

Explanation:

Given:

v₀ = 63 m/s

a = 2.8 m/s²

t = 4.0 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (63 m/s) (4.0 s) + ½ (2.8 m/s²) (4.0 s)²

Δx = 274.4 m

Rounded to two significant figures, the displacement is 270 meters.

6 0
3 years ago
A perfectly elastic collision occurs between a 15.0-kg mass traveling at 3.50 m/s and a 9.00-kg mass traveling at 2.35 m/s. if t
BaLLatris [955]
Momentum is conserved in a collision. Momentum is mass*velocity, so you can find your answer by calculating initial and final momentums and setting them equal to each other.

15kg * 3.50 m/s + 9kg * 2.35 m/s = 73.65 kg m/s

73.65 = 9 * 2.8 + 15x

solve for x
x= 3.23

The final velocity is 3.23 m/s
5 0
3 years ago
An airplane was moving 1200 km per minute traveling in a north-to-south direction when they were spotted by air traffic control.
Feliz [49]

Its velocity was 20 km/s southward

7 0
3 years ago
Read 2 more answers
At takeoff, a commercial jet has a speed of 72 m/s. Its tires have a diameter of 0.89 m. Part (a) At how many rev/min are the ti
34kurt

Answer:

a) Revolutions per minute = 2.33

b) Centripetal acceleration = 11649.44 m/s²

Explanation:

a) Angular velocity is the ratio of linear velocity and radius.

Here linear velocity = 72 m/s

Radius, r  = 0.89 x 0. 5 = 0.445 m

Angular velocity

         \omega =\frac{72}{0.445}=161.8rad/s

Frequency

         f=\frac{2\pi}{\omega}=\frac{2\times \pi}{161.8}=0.0388rev/s=2.33rev/min

Revolutions per minute = 2.33

b) Centripetal acceleration

               a=\frac{v^2}{r}

  Here linear velocity = 72 m/s

  Radius, r  = 0.445 m

Substituting

   a=\frac{72^2}{0.445}=11649.44m/s^2

Centripetal acceleration = 11649.44m/s²

6 0
3 years ago
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