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3 years ago

Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?

Physics

1 answer:

ohaa [14]3 years ago

4 0

Answer:

C. 212,000 years

Explanation:

believe me it's correct.....and you're welcome :)

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Two sacks contain the same number of identical apples and are separated by a distance r. The two sacks exert a gravitational for

stepan [7]

Answer:

Explanation:

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3 years ago

Describe how newtons third law is related to fluid pressure.

Hatshy [7]

Fish swimming forward in the water, the water gets pushed backward because the fish moving forward is forcing the water to move backward, the motion forward and backward are the same, they are opposite and equal.

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4 years ago

If a car is moving with a speed of 5 km/h on a highway. Find the distance travelled by the car in 2 hours?.

grin007 [14]

Answer:

Distance = 10 kilometers.

Explanation:

Given the following data;

Speed = 5km/h

Time = 2 hours

To find the distance traveled;

Distance = speed * time

Distance = 5 * 2

Distance = 10 kilometers

Therefore, the distance travelled by the car is 10 kilometers.

5 0

3 years ago

What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o

leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,

$d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}$

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

$\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}$

This value can be used to determine the time for the pellet through the barrel:

$t = \frac{d}{\overline{v}}=\frac{0.6m}{77.5\frac{m}{s}}\approx0.00774s$

Finally, we can use the above to calculate the force:

$F = ma = m\frac{2d}{t^2} = 0.007kg\cdot \frac{2\cdot 0.6 m}{0.00774^2 s^2}\approx 140.22N$

8 0

3 years ago

Two water balloons of mass 0.75 kg collide and bounce off of each other without breaking. Before the collision, one water balloo

bagirrra123 [75]

By the law of momentum conservation:-
=>m¹u¹ + m²u² = m1v1 + m²v² {let East is +ve}
=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
<span> =>v¹ = 2.25 m/s (East) </span>

5 0

3 years ago