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hjlf
3 years ago
15

If you burn 10 kilograms of wood in a fire (combustion) what is the weight of the products after the fire has finished burning t

he wood?
Chemistry
1 answer:
sleet_krkn [62]3 years ago
3 0

The answer is: the weight of products is is equal the weight of the wood plus the weight of oxygen that was used to burn that wood, so weigh of the product is greater than 10 kilograms.

Conservation of mass (mass is never lost or gained in chemical reactions), during chemical reaction no particles are created or destroyed, the atoms are rearranged from the reactants to the products.

In this example wood (mostly carbon) and oxygen are reactants and carbon dioxide (mostly) is product of reaction.

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What is the molarity of a solution made by dissolving 1.25 mol of HCl in enough
Ronch [10]

Answer:

Explanation:

C

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3 years ago
How many molecules of BH3 are in 14.32 grams of BH3?
kkurt [141]

Answer:

6.23 x 10^23 molecules

Explanation:

First find the number of moles of BH3 from the information given. We know the amount of grams present and we can find the molar mass which is 13.84.

We know that moles is grams divided by molar mass so we get 14.32/13.84 which is 1.03 moles.

Finally, to figure out the number of molecules, we multiply 1.03 by Avogadro's number which is 6.022x10^23 and we get 6.23x10^23 molecules.

3 0
4 years ago
1. Which graph shows the melting of crystalline solids? Explain your reasoning.
madreJ [45]
(1) The melting of a crystalline solid is best depicted by the second graph. This is because, the second graph shows a horizontal line which means that for a while there was no change in temperature. This zone is the latent heat of fusion. 

(2) The first graph shows the graph of a solid that is just heated but does not experience phase change. However, the second graph shows a solid that changes phase (from crystal/solid to liquid). 
8 0
4 years ago
What is the significance of equivalence point in acid base titrations?
iren2701 [21]

Hey there!

The equivalence is point in a titration is the point at which you have neutralized all of your base/acid with your titrant acid/base from a buret. This can be seen with indicators which change color at the equivalence point in a titration to signal to you that all of your base/acid has been reacted with. For example, all your molecules of OH⁻ from a NaOH base in a beaker have been neutralized by H⁺of HCl acid from your titrant in a buret leaving only Na⁺ ions and Cl⁻ ions and neutral H₂O molecules.

7 0
3 years ago
Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta
scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion=\frac{Volume}{Time}

Effusion rate of oxygen gas after time t = E=\frac{4.64 mL}{t}

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = E'=\frac{3.12 mL}{t}

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{E}{E'}=\sqrt{\frac{M'}{M}}

\frac{\frac{4.64 mL}{t}}{\frac{3.12 mL}{t}}=\sqrt{\frac{M'}{32 g/mol}}

M' = 70.77 g/mol

70.77 g/mol is the molar mass of the unknown gas.

8 0
3 years ago
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