Answer:
for the cellular respiration the human body needs 1.424 E21 molecules of glucose
Explanation:
mass glucose = 24 g
∴ Mw glucose = 180.156 g/mol
∴ 1 mol ≡ 6.022 E23 molecules
⇒ mol glucose = (24 g)×(mol/180.156 g) = 0.1332 mol glucose
⇒ molecules glucose = (0.1332 mol glucose)×(6.022 E23 molecules/mol)
⇒ molecules glucose = 1.424 E21 molecules
Hello!
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:







Answer:
The temperature is approximately 205 Kelvin
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I Hope this helps, greetings ... Dexteright02! =)
RNA strand is called ribonucleic acid
<span>Accelerants might be what you are looking for. Hope this helps.</span>