The elapsed time when the particle returns to the origin is determined from the ratio of initial velocity and acceleration of the particle.
<h3>Time of motion of the particle</h3>
The time of motion of the particle is calculated by applying Newton's second law of motion.
F = ma
F = m(v)/t
where;
- t is time of motion of the particle
- m is mass of the particle
- v is velocity of the particle
a = v - u/t
v = u + at
when the particle returns to the origin, direction of u, = negative.
final velocity = 0
0 = -u + at
at = u
t = u/a
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Answer:
The the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s
Explanation:
We are given that
Angular acceleration, 
Diameter of the wheel, d=21 cm
Radius of wheel,
cm
Radius of wheel, 
1m=100 cm
Magnitude of total linear acceleration, a=
We have to find the linear speed of a at an instant when that point has a total linear acceleration with a magnitude of 1.7 m/s2.
Tangential acceleration,


Radial acceleration,
We know that

Using the formula

Squaring on both sides
we get






Hence, the the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s
Answer:

Explanation:
As we know that the sixth order maximum will have path difference given as

here we know that
N = order of maximum

now we have

so we know that


Answer:
Average force will be equal to 2908.57 N
Explanation:
We have given mass of the ball m = 46 gram = 0.046 kg
Let velocity at which ball is projected is u m/sec
Angle at which ball is projected 
Range of the ball is given R = 200 m
Range is equal to 


u = 44.27 m/sec
Change in momentum of the ball is equal to 
Time of impact is given 
Force is equal to rate of change of momentum
So force 
Force will be equal to 2908.57 N
Answer:
found in the nucleus, has mass of one amu
Explanation: