Question

Calculate the electric charge of the glass ball

Answer 1

Answer:

As per Coulomb's law we know that force between two charges is given as

F = \frac{kq_1q_2}{r^2}F=

r

2

kq

1

q

2

here we know that

q_1 = 2.5 \times 10^{-6} Cq

1

=2.5×10

−6

C

q_2 = -5.0 \times 10^{-6} Cq

2

=−5.0×10

−6

C

r = 0.0050 mr=0.0050m

now from above formula we will have

F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=

(0.0050)

2

(9×10

9

)(2.5×10

−6

)(5×10

−6

)

F = 4500 NF=4500N

so they will attract towards each other as they are opposite in nature with force F = 4500 N