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3 years ago

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If a person is standing up in a moving bus that stops suddenly,the person can easily fall forwards.Has a force acted to push the

person forwards? Use Newton's law of motion to explain what is happening.

2 answers:

cupoosta [38]3 years ago

8 0

That is inertia, 1st law of motion, no net force is applied

Kamila [148]3 years ago

6 0

Answer:

i think gravity created a force strong enough to push him down.but it also depends how slow or fast the bus is going

Explanation:

gravity as we all now it is pretty strong so if the bus is going fast then the person standing up will fall but if the bus is going pretty slow then it'll just nudge him.

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blsea [12.9K]

Answer:

True

Explanation:

7 0

2 years ago

Read 2 more answers

An engineer has the task of producing an aluminum alloy with a density of 3.0 grams per cubic centimeter. She comes up with the

pochemuha

Answer:

The best option is for the following option m = 15 [g] and V = 5 [cm³]

Explanation:

We have that the density of a body is defined as the ratio of mass to volume.

$Ro =m/V$

where:

Ro = density = 3 [g/cm³]

Now we must determine the densities with each of the given values.

<u>For m = 7 [g] and V = 2.3 [cm³]</u>

$Ro=7/2.3\\Ro=3.04 [g/cm^{3} ]$

<u>For m = 10 [g] and V = 7 [cm³]</u>

<u /> $Ro=10/7\\Ro=1.42[g/cm^{3} ]\\$ <u />

<u>For m = 15 [g] and V = 5 [cm³]</u>

<u /> $Ro=15/5\\Ro=3[g/cm^{3} ]\\$ <u />

<u>For m = 21 [g] and V = 8 [cm³]</u>

<u /> $Ro=21/8\\Ro=2.625[g/cm^{3} ]\\$ <u />

5 0

3 years ago

A system releases 255 cal of heat to the surroundings while delivering 428 cal of work. what is the change in internal energy of

vichka [17]

Answer:-683 cal

Explanation:

Given

Heat released by system Q=-255 cal

as heat released is taken as negative and vice-versa

Work done by system W=428 cal

From First law of thermodynamics

$Q=\Delta +W , where \Delta U$ =change in internal Energy

$\Delta U=-255-428=-683$

7 0

3 years ago

When gravitational field lines get farther apart, the gravitational field _________.

kupik [55]

<span>b. becomes weaker
try this </span>

3 0

3 years ago

Help me please I can't get the final step

inna [77]

Answer:

$\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}$

Explanation:

<u>Dimensional Analysis</u>

It's given the relation between quantities A, B, and C as follows:

$\displaystyle A=\frac{3}{2}B^mC^n$

and the dimensions of each variable is:

$A=L^2T^2$

$B=LT^{-1}$

$C=LT^2$

Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

$\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n$

Operating:

$L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)$

$L^2T^2=L^{m+m}T^{-m+2n}$

Equating the exponents:

$m+n=2$

$-m+2n=2$

Adding both equations:

$3n=4$

Solving:

$n=4/3$

$m=2-4/3=2/3$

Answer:

$\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}$

6 0

3 years ago