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Snezhnost [94]
3 years ago
10

Which of the following statements about neurons are NOT true?

Physics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

The correct answers to the question are

The following statements about neurons are NOT true

A. The resting membrane potential is generally in the range of -40 mv to -75 mv.

C. Neurons repolarize by opening chloride channels on the membrane.

D. An action potential can occur when the neuron's sodium gates open.

Explanation:

A. The resting membrane potential is generally in the range of -40 mv to -75 mv.

Not true the resting potential for neurons range from -70 to -80 mv

B. Maintaining resting membrane potential requires the use of energy from ATP True

The potential of the membrane arises from the splitting of potassium ions from the intracellular anions by agents powered by ATP

C. Neurons repolarize by opening chloride channels on the membrane

Not True

Repolarization occurs by the outward transit of the positively charged K⁺ from the cell

D. An action potential can occur when the neuron's sodium gates open.

Not True

An action potential takes place once the neuron transmits information along an axon. An action potential results when different ions pass through the membrane of the neuron

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Alex787 [66]

Answer: Mr. Whitmore would need 7 or more students ( 7.17) to make the box start moving and go outside

Explanation:

Given that;

friction force of ground box = 68 N

student of 7th grade = n

Whitmore can apply a force of 25 N

every other 7th grade student can apply a force of 6 N.

now

friction force = forced applied by whitmore + total force ny 7th grade student

we substitute

68 = 25 + 6n

6n = 68 - 25

6n = 43

n = 43/6

n = 7.17

Therefore Mr. Whitmore would need 7 or more students ( 7.17) to make the box start moving and go outside

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3 years ago
What is the unit of measurement of velocity
melomori [17]

Usually the unit of measurement of velocity is meters per second or m/s

7 0
3 years ago
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Our Solar System's planets formed when fragments in space joined together to form growing spheres in a process known as ____​
Nimfa-mama [501]

Answer: accretion......

8 0
4 years ago
A truck with a heavy load has a total mass of 7100 kg. It is climbing a 15∘ incline at a steady 15 m/s when, unfortunately, the
Andrej [43]

Answer:

The load has a mass of 2636.8 kg

Explanation:

Step 1 : Data given

Mass of the truck = 7100 kg

Angle = 15°

velocity = 15m/s

Acceleration = 1.5 m/s²

Mass of truck = m1 kg

Mass of load = m2 kg

Thrust from engine = T

Step 2:

⇒ Before the load falls off, thrust (T) balances the component of total weight downhill:

T = (m1+m2)*g*sinθ

⇒ After the load falls off, thrust (T) remains the same but downhill component of weight becomes  m1*gsinθ .

Resultant force on truck is F = T – m1*gsinθ  

F causes the acceleration of the truck: F= m*a

This gives the equation:

T – m1*gsinθ = m1*a  

T = m1(a + gsinθ)

Combining both equations gives:

(m1+m2)*g*sinθ = m1*(a + gsinθ)

m1*g*sinθ + m2*g*sinθ =m1*a + m1*g*sinθ

m2*g*sinθ = m1*a

Since m1+m2 = 7100kg, m1= 7100 – m2. This we can plug into the previous equation:

m2*g*sinθ = (7100 – m2)*a

m2*g*sinθ = 7100a – m2a

m2*gsinθ + m2*a = 7100a

m2* (gsinθ + a) = 7100a

m2 = 7100a/(gsinθ  + a)

m2 = (7100 * 1.5) / (9.8sin(15°) + 1.5)

m2 = 2636.8 kg

The load has a mass of 2636.8 kg

6 0
3 years ago
The force of Earth's gravity on a capsule in space will lessen as it moves farther away. If the capsule moves to twice its dista
Bess [88]

Answer: One quarter of the force

Explanation:

According to Newton's law of Gravitation, the force F exerted between two bodies of masses m1 and m2  and separated by a distance r  is equal to the product of their masses and inversely proportional to the square of the distance:

F=G\frac{(m1)(m2)}{r^2}    (1)

Where Gis the gravitational constant

This means that the gravity force decreases when the distance between these two bodies increases.

In this context, if the distance between the capsule and the Earth increases twice, the new distance will be 2r.

Substituting this distance in (1):

F=G\frac{(m1)(m2)}{(2r)^2}    (2)

F=G\frac{(m1)(m2)}{4r^2}    

<u>Finally:</u>

F=\frac{1}{4}G\frac{(m1)(m2)}{r^2} >>>This means the force toward Earth becomes one quarter "weaker"

3 0
3 years ago
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