What kind of weather would an occuluded front likely bring
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The time taken to complete her run is 1.9 hr.
<u>Explanation:</u>
Speed is a scalar quantity and it is defined as the ratio of distance covered to the time taken to cover that distance. As distance is also a scalar quantity, so the directions given in the problem can be ignored. Thus, the distance covered by the jogger is the sum of kilometers given in problem.
Distance covered = 6+5+4 = 15 km
And the speed is given as 8 km/hr.
So the time taken will be ratio of distance to speed.
So the jogger will take 1.9 hr to complete her run.
The average speed of the plane is 875.999 m/s.
Average speed can be defined as the ratio of total distanced travelled by the object to that of total time taken to cover the distance.
Mathematically, Average speed = Av =
According to the question,
Speed of the plane away from its base V₁ = 730 m/s
Speed of the plane when it flies back V₂ = 1095 m/s
Plane flies the distance D = 404 km
Total Distance covered by the plane S = 404 * 2 km
(because the distance travelled by the plane when going away from the base and then flying back to the base is same)
Therefore S = 808 km = 808 ˣ 10³ m
Time taken by the plane while flying away from the base T₁ =
T₁ = = 553.425 s
Time taken by the plane while flying back to the base T₂ =
T₂ = = 368.949s
Total Time T = T₁ + T₂ = 922.375 s
Therefore Av =
= m/s
= m/s
= 875.999 m/s
The average speed of the plane will be 875.999 m/s.
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