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faltersainse [42]
3 years ago
10

A car drives 20 miles north and then 3 miles south. what is the displacement or the car

Physics
2 answers:
Phoenix [80]3 years ago
6 0

Answer:

17 miles north

Explanation:

kobusy [5.1K]3 years ago
5 0
An:
Displacement is 16.
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A point charge with a charge q1 = 4.00 μC is held stationary at the origin. A second point charge with a charge q2 = -4.10 μC mo
GrogVix [38]

Answer:

W = -0.480 J

Explanation:

given,

q₁ = 4 μC

q₂ = -4.10 μC

W = kq_1q_2(\dfrac{1}{a}+\dfrac{1}{b})

b = \sqrt{(0.27-0)^2+(0.27-0)^2}

b = 0.381

k = 8.99 × 10⁹ Nm²/C²

W = 8.99\times 10^9\times 4\times 10^{-6}\times (-4.1 \times 10^{-6})(\dfrac{1}{0.17}+\dfrac{1}{0.381})

W = [-147.436\times (5.88-2.62)\times 10^{-3}]J

W = -0.480 J

Work done by the electric force W = -0.480 J

4 0
2 years ago
A very humble bumble bee is flying horizontally due North at a constant speed of 3.11 m/s. At the current location of the bumble
Reil [10]

To solve this problem we will apply the concepts of the Magnetic Force. This expression will be expressed in both the vector and the scalar ways. Through this second we can directly use the presented values and replace them to obtain the value of the magnitude. Mathematically this can be described as,

\vec{F_B} = q(\vec{V}\times \vec{B})

F_B = q|v||B| sin\theta

Here,

q = Charge

v = Velocity

B = Magnetic field

\theta = \text{Angle between } \vec{B} \text{ and } \vec{V}

Our values are given as,

\theta = 35.7\°

q = 22.5*10^{-9}C

B = 1.05*10^{-5}T

v = 3.11m/s

Replacing,

F_B = (22.5*10^{-9}C)(3.11 \times 1.05*10^{-5}) sin(35.1\°)

F_B = 4.224*10^{-13}N

Therefore the size of the magnetic force acting on the bumble bee is 4.22*10^{-13}N

3 0
3 years ago
Do you have to keep citing the same source
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4 0
3 years ago
How does 3rd class lever make our work easier
sineoko [7]
In a third class lever, the effort is located between the load and the fulcrum. If the fulcrum is closer to the load, then less effort is needed to move the load. If the fulcrum is closer to the effort, then the load will move a greater distance. ... These levers are useful for making precise movements.
7 0
2 years ago
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A pipe open at both ends has a fundamental frequency of 220 Hz when the temperature is 0°C. (a) What is the length of the pipe?
Allushta [10]

Explanation:

It is given that,

Fundamental frequency, f = 220 Hz

(a) We know that at 0 degrees, the speed of sound in air is 331 m/s.

For open pipe, \lambda=2l

l is the length of pipe

Also,

v=f\lambda

l=\dfrac{v}{2f}=\dfrac{331}{2\times 220}=0.75\ m

(b) Let f' is the fundamental frequency of the pipe at 30 degrees and v' is its speed.

v'=331\sqrt{1+\dfrac{T}{273}}

v'=331\sqrt{1+\dfrac{30}{273}}

v' = 348.71 m/s

So, f'=\dfrac{v'}{\lambda}

f'=\dfrac{348.71}{2\times 0.75}

f' = 232.4 Hz

Hence, this is the required solution.

8 0
3 years ago
Read 2 more answers
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