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Lubov Fominskaja [6]
3 years ago
15

what essential characteristic does a good experiment have? a. a control group is given the experimental treatment. b. a single v

ariable is tested. c. a control is used. d. both b and c
Physics
1 answer:
madreJ [45]3 years ago
8 0
A. A control group is given the experimental treatment.
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If for a given pair of media CR
nika2105 [10]

CR​ < CY​ < CB​

<h3>Which factors affect the critical angle for a given pair of media?</h3>

The factors which affect the critical angle are

(a) The colour (or wavelength) of light

(b) The temperature

(i) Effect of colour of light: The critical angle for a pair of media is less for the violet light and more for the red light. Thus the critical angle increases with the increase in wavelength of light.

(ii) Effect of temperature: The critical angle increases with increase in temperature because on increasing temperature of medium, its refractive index decreases.

According to the question,

μ 1​ sinCR​ =1

μ 2​ sinCY =1

μ 3​ sinCB​ =1

μ 1​ > μ 2​  and μ 2​ > μ 3

⟹μ 1​ > μ 2​ > μ 3

CR​ < CY​ < CB​

Thus,

The critical angle increases with the increase in wavelength of light.

Learn more about wavelength of light here:

brainly.com/question/27557868

#SPJ1

7 0
2 years ago
How does fungi, snails, earthworms, and pill bugs return nutrients to the ecosystem?
luda_lava [24]
They decompose and leave their nutrients in the earth. 
4 0
3 years ago
A doppler fetal monitor is a hand-held ultrasound device that is used to detect a fetal heartbeat in prenatal care. The device w
Stolb23 [73]

Answer:

The maximum speed of the heart wall during the motion is 0.032 m/s

Explanation:

Given:

A = amplitude of vibration = 1.7 mm = 1.7x10⁻³m

f = frequency = 3 Hz

The angular velocity is:

w=2\pi f=2\pi *3=18.85Hz

The maximum speed of the heart wall during the motion is equal to:

V=Aw=1.7x10^{-3} *18.85=0.032m/s

6 0
3 years ago
Please help quick please its a test
navik [9.2K]

Answer:

Im pretty sure its y!

Explanation:

6 0
3 years ago
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
arsen [322]

Answer:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates  to find the horizontal distance traveled by the electron when it hits the plate.

acceleration a=qE/m=1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}=7*10^{14} m/s

now we find the horizontal distance traveled by electrons hit the plates

horizontal distance

X=u[2y/a]^{1/2}

=4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}

=3*10^{-2}= 3 cm

5 0
4 years ago
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