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harkovskaia [24]
3 years ago
7

Why is respiration an exothermic reaction? A. a large amount of energy is released into its surroundings B. the heat content, q,

of the reaction is positive C. a large amount of energy is required to activate the reaction D. there is no exchange of energy between the system and the surrounding

Physics
2 answers:
Rina8888 [55]3 years ago
4 0
A. a large amount of energy released into its surrounding

During the respiration, glucose molecules are converted to other molecules in a series of steps. They finally end up as as carbon-dioxide and water.

The overall reaction is

<span>C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + 2805 kJ
</span>
The reaction is exothermic reaction because <span>C=O and O-H bonds in the products are so much more stable than the bonds in the reactants.
</span>
Bond energy is the average needed to break a bond.

Some bond energies are:
C-C = 347 kJ/mol
C-H = 413kJ/mol;
C-O = 358 kJ/mol;
O-H = 467 kJ/mol;
O=O = 495 kJ/mol;
<span>C=O = 799 kJ/mol</span>



xxTIMURxx [149]3 years ago
4 0
Respiration is an exothermic reaction because a large amount of energy is released into it's surroundings, which is B. An exothermic reaction is a reaction that releases heat or energy into it's surroundings. During respiration, energy is released into the surrounding. Therefore it is an exothermic reaction. An endothermic reaction on the other hand takes in heat or energy from it's surrounding. Hope i helped.
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3 years ago
In midair an M = 145 kg bomb explodes into two pieces of m1 = 115 kg and another, respectively. Before the explosion, the bomb w
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Answer:

v_2=-133.17m/s, the minus meaning west.

Explanation:

We know that linear momentum must be conserved, so it will be the same before (p_i) and after (p_f) the explosion. We will take the east direction as positive.

Before the explosion we have p_i=m_iv_i=Mv_i.

After the explosion we have pieces 1 and 2, so p_f=m_1v_1+m_2v_2.

These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.

Since we know momentum must be conserved we have:

Mv_i=m_1v_1+m_2v_2

Which means (since we want v_2 and M=m_1+m_2):

v_2=\frac{Mv_i-m_1v_1}{m_2}=\frac{Mv_i-m_1v_1}{M-m_1}

So for our values we have:

v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s

5 0
3 years ago
What is the approximate weight of a 20-kg cannonball on Earth? 2 N 20 N 196 N 1,960 N
Margaret [11]
Since weight is the force an object is exerting on another object, and the formula to calculate force is Force = Mass * Acceleration, the answer to your question is 196 N, since the mass of the cannonball times Earth's gravitational pull equals 196 N.
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4 years ago
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Explanation:

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5 0
3 years ago
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