Answer:
98 N
Explanation:
The weight of an object is given by:
where
m is the mass of the object
is the acceleration due to gravity
In this problem, the mass of the lemur is m=10 kg, so its weight is
1. A pendulum bob (the mass) is made from a sphere (ball) filled with water. What would happen to the frequency of vibration of
1 answer:
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F = 1440 N. The repulsion force between two identical charges, each -8.00x10⁻⁵C separated by a distance of 20.0 cm is 1440 N.
The easiest way to solve this problem is using Coulomb's Law given by the equation , where k is the constant of proportionality or Coulomb's constant, q₁ and q₂ are the charges magnitude, and r is the distance between them.
We have to identical charges of -8.00x10⁻⁵C, are separated by a distance of 20.0 cm, and we need to know the force of repulsion between the charges.
First, we have to convert 20.0 cm to meters.
(20.0 cm x 1m)/100cm = 0.20 m
Using the Coulomb's Law equation: