Use the Henderson-Hasselbach equation:
pH = pKa + log[base]/[acid]
pH = -log(1.7 x 10^-5) + log(0.590/0.130) = 5.43
Answer:
112.2L
Explanation:
Volume (V) = 300g
Temperature (T) = 822K
Pressure (P) = 0.9atm
using the ideal gas equation;

Molar gas constant (R) = 
Mole (n) =
Molar mass of Mercury = 200.59g/mol

= 1.496mol
Now, the volume can be calculated;
V = 
∴Volume of mercury = 
The given reaction is a combustion reaction, since a hydrocarbon is burning in presence of oxygen
Molar mass of C6H12O6 = 6x12 + 12x1 + 6x16 = 180g
SO mass of 1 mole of C6H12O6 = 180g
mass of 0.5 mole of C6H12O6 = 0.5 x180g = 90g