The reactant that will be the best reactant for a nucleophilic aromatic substitution is NO₂- NO₂. The correct option is b.
<h3>What is nucleophilic
aromatic substitution?</h3>
Nucleophilic aromatic substitution is a substitution process of nucleophile substance is substituted by halides in an aromatic ring. Aromatic compounds contain this type of substitution.
In option b, the compound is the one nitroxide group substituted by halogen, that is fluorine. The fluorine group is substituted in these given aromatic compounds.
Thus, the correct option is b, NO₂- NO₂.
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The question is incomplete. Your most probably complete question is given below:
NO₂F
NO₂- NO₂-F
CH₃-O
CH₃-O-F
Answer:
Increases, remain constant
Explanation:
In the light spectrum, the photons with a higher frequency (hence smaller wavelengths) have higher energy. The lower the energy the lower the frequency and longer the wavelengths. The intensity of light does not change the energy levels of these photons. The higher the intensity the higher the density of the photoelectrons.
Answer: 100 times
Explanation: Since logaritms are about exponent of base ten.The concentration will be 10^2 or 100 times greater concentration.
Hrxn = Q reaction / mol of reaction
mol of reaction = M * V = 10 * 1 = 10 mmol = 0.01 mol
Q water = m * C * (Tf - Ti)
= (10 + 10) (4.184) (26-20) = 502.08 J
Q reaction = - Q water = -502.08 J
Hrxn = -502.08 / (0.01) = - 50208 J = - 50.21 kJ/mol
