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2 years ago

What’s the difference in kinetic energy of solids, liquids, and gases.

Chemistry

1 answer:

k0ka [10]2 years ago

4 0

Answer:

Solids have the lowest kinetic energy so vibrate very little. Liquids have more kinetic energy so particles slide past each other. Gases have the most kinetic energy so fly around in the air

Explanation:

Brainliest much appricated

Have a good day!

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Write a net ionic equation that describes a slightly basic solution resulting from dissolving nac2h3o2 in water. Identify all of

Natali [406]

Answer: The net ionic equation will be as follows.

$CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)$

Explanation:

The chemical equation for the given reaction is as follows.

$CH_{3}COONa(aq) + H_{2}O(l) \rightleftarrow CH_{3}COOH(aq) + NaOH(aq)$

We know that a strong acid or base will dissociate completely into a solvent whereas a weak acid or base dissociates partially into the solvent. Hence, the ionic equation will be as follows.

$CH_{3}COO^{-}(aq) + Na^{+}(aq) H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + Na^{+}(aq) + OH^{-}(aq)$ Now, we will cancel the spectator ions from the above equation. Therefore, the net ionic equation will be as follows.

$CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)$

or, $C_{2}H_{3}O^{-}_{2}(aq) + H_{2}O(l) \rightleftharpoons HC_{2}H_{3}O_{2}(aq) + OH^{-}(aq)$

4 0

3 years ago

If 200. g of water at 20°C absorbs 41 840 J of energy, what will its final temperature be? (Specific Heat of water is 4.184 J/g*

Elena-2011 [213]

Answer: The final temperature will be $70^0C$

Explanation:

To calculate the specific heat of substance during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed =41840 J

c = specific heat = $4.184J/g^0C$

m = mass of water = 200 g

$T_{final}$ = final temperature =?

$T_{initial}$ = initial temperature = $20^0C$

Now put all the given values in the above formula, we get:

$41840J=200g\times 4.184J/g^0C\times (T_{final}-20)^0C$

$T_{final}=70^0C$

Thus the final temperature will be $70^0C$

3 0

2 years ago

Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.

BaLLatris [955]

Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = 240.9

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

Mr of (O₃)₃ = (16 × 3) × 3 = 144

Now we can find percentage composition / percentage by mass of oxygen.

% composition = $\frac{Mr\ of\ oxygen\ in\ compound}{Mr\ of\ compound}$ × 100

% composition = $\frac{144}{240.9}$ × 100 = 59.776%

∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).

8 0

2 years ago

5 QUESTIONS PLZ ANSWER ASAP SCIENCE

sweet-ann [11.9K]

A. Plastic is a good insulator.

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2 years ago

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If an alloy is formed that is 50 mol% silver and 50 mol% gold, what is the karat number of the alloy?

Allisa [31]

Answer : 12 karat

Explanation : When pure gold is considered to be 24 karat then if its 50 mol% silver and 50 mol% silver then using karat scale calculation;

Karat/24 X 100 = 50 mol% (for gold) in alloy

So, Karat = (50 X 24) / 100 = 12 karat.

Hence the alloy will be of 12 karat.

7 0

3 years ago

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