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Zanzabum
3 years ago
14

What is the correct way to write the molar mass of iron oxide as a conversion factor

Chemistry
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

3rd option.

159.7g Fe2O3 / 1 mol Fe2O3

Explanation:

The correct way to write the molar mass of iron oxide as a conversion factor is illustrated below:

Mass of Fe2O3 = 159.7g

Number of mole = 1 mole

Molar Mass of Fe2O3 =?

Molar Mass = Mass /number of mole

Molar Mass =

159.7g Fe2O3 / 1 mol Fe2O3

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Artemon [7]

Answer:

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Explanation:

6 0
3 years ago
Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

5 0
3 years ago
Complete this example: A 0.67 molal solution was
Lynna [10]

Answer:

A then C

Explanation:

3 0
2 years ago
The reaction, 2C4H10 (g) + 13O2 (g) à 8CO2 (g) + 5H2O (g), is the combustion of butane. What occurs as the reaction proceeds?
Solnce55 [7]
The reaction, 2 C4H10 (g) + 13 O2 (g) = 8 CO2 (g) + 5 H2O (g), is the combustion of butane.   A combustion reaction involves the reaction of a hydrocarbon with oxygen producing carbon dioxide and water. This reaction is exothermic which means it releases energy in the form of heat. Therefore, as the reaction proceeds,a heat energy is being given off by the reaction. This happens because the total kinetic energy of the reactants is greater than the total kinetic energy of the products. So, the excess energy should be given off somewhere which in this case is released as heat.
7 0
3 years ago
Ba(OH)2 Ba+2 + 2 OH- (dissolved in solution). Which will NOT happen to the equilibrium of this solution as H+ ions are added? H+
prohojiy [21]

Answer:

The reaction will move to the left.

Explanation:

  • For the reaction:

<em>Ba(OH)₂ = Ba²⁺ + 2OH⁻,</em>

<em>Ba(OH)₂ is dissociated to Ba²⁺ and 2OH⁻.</em>

  • If H⁺ ions are added to the equilibrium:

H⁺ will combine with OH⁻ to form water.

<em>So, the concentration of OH⁻ will decrease and the equilibrium is disturbed.</em>

<em />

<em>According to Le Châtelier's principle: </em>when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

  • So, the reaction will move to the right to suppress the effect of decreasing OH⁻ concentration.

  • The base will dissociate to form more OH⁻ and thus, the quantity of Ba(OH)₂ will decrease.

<em>So, the right choice is: the reaction will move to the left, is the choice that will not happen to the equilibrium.</em>

5 0
3 years ago
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