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Genrish500 [490]
3 years ago
8

A) infrared energy B) microwave energy C) radio wave energy

Physics
2 answers:
nevsk [136]3 years ago
7 0

Answer:

A) infrared energy

Explanation:

timama [110]3 years ago
5 0

Answer:

Infrared energy

Explanation:

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Convert 1 second in to solar day<br>​
jeka94

1 Days to Seconds = 86400 70 Days to Seconds = 6048000
2 Days to Seconds = 172800 80 Days to Seconds = 6912000
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When a wire loop is connected to a battery, what is produced in the loop?
Vinil7 [7]

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magnetic field

Explanation:

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3 years ago
What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4
mrs_skeptik [129]

Answer:

x = 2\sqrt 2

Explanation:

Given

Hypotenuse = 4

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

x^2 + x^2 = 4^2 --- i.e. the other legs are equal

So, we have:

2x^2 = 16

Divide both sides by 2

x^2=8

Take square roots of both sides

x = \sqrt 8

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x = 2\sqrt 2

5 0
3 years ago
Read 2 more answers
High-energy electromagnetic waves are released when an atom undergoes gamma decay. Which of the following is usually ejected sim
amm1812
B. An alpha or beta particle
4 0
4 years ago
The High Speed Industrial Drill With Diameter Of 98 Cm Develops 5.85hp At 1900 Rpm. What Torque And Force Is Applied To The Dril
STatiana [176]

Answer:

The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.

Explanation:

Given:-

- The diameter of the drill bit, d = 98 cm

- The power at which drill works, P = 5.85 hp

- The rotational speed of drill, N = 1900 rpm

Find:-

What Torque And Force Is Applied To The Drill Bit?

Solution:-

- The amount of torque (T) generated at the periphery of the cutting edges of the drilling bit when it is driven at a power of (P) horsepower at some rotational speed (N).

- The relation between these quantities is given:

                         T = 5252*P / N

                         T = 5252*5.85 / 1900

                         T = 16.171 Nm

- The force (F) applied at the periphery of the drill bit cutting edge at a distance of radius from the center of drill bit can be determined from the definition of Torque (T) being a cross product of the Force (F) and a moment arm (r):

                          T = F*r

Where,   r = d / 2

                          F = 2T / d

                          F = 2*16.171 / 0.98

                          F = 33 N

Answer: The torque applied by the drill bit is T = 16.2 Nm and the cutting force of the drill bit is F = 33 N.

4 0
3 years ago
Read 2 more answers
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