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navik [9.2K]
3 years ago
7

Two electrostatic point charges of +53.0 µC and +44.0 µC exert a repulsive force on each other of 166 N. What is the distance be

tween the two charges? The value of the Coulomb constant is 8.98755 × 109 N · m2 /C 2 . Answer in units of m
Physics
1 answer:
Crazy boy [7]3 years ago
3 0

Answer:

0.355 m

Explanation:

Data provided in the question:

Charges, q₁ = 53.0 µC = 53.0 × 10⁻⁶ C and q₂ = 44.0 µC = 44.0  × 10⁻⁶ C

Repulsive force exerted by the charges, F = 166 N

The value of Coulomb constant, k = 8.98755 × 10⁹ N·m²/C²

Now,

The Force exerted between the charges is given as = \frac{kq_1q_2}{r^2}

Thus,

166 N = \frac{8.98755\times10^9\times53\times10^{-6}44\times10^{-6}}{r^2}

or

r² = \frac{8.98755\times10^9\times53\times10^{-6}44\times10^{-6}}{166}

or

r = 0.355 m

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Two balls, each with a mass of 0.890 kg, exert a gravitational force of 8.06 × 10−11 n on each other. how far apart are the ball
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A horizontal circular platform rotates counterclockwise about its axis at the rate of 0.945 rad/s. You, with a mass of 69.7 kg,
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Answer:

317.22

Explanation:

Given

Circular platform rotates ccw 93.1kg, radius 1.93 m, 0.945 rad/s

You 69.7kg, cw 1.01m/s, at r

Poodle 20.2 kg, cw 1.01/2 m/s, at r/2

Mutt 17.7 kg, 3r/4

You

Relative

ω = v/r

= 1.01/1.93

= 0.522

Actual

ω = 0.945 - 0.522

= 0.42

I = mr^2

= 69.7*1.93^2

= 259.6

L = Iω

= 259.6*0.42

= 109.4

Poodle

Relative

ω = (1.01/2)/(1.93/2)

= 0.5233

Actual

ω = 0.945- 0.5233

= 0.4217

I = m(r/2)^2

= 20.2*(1.93/2)^2

= 18.81

L = Iω

= 18.81*0.4217

= 7.93

Mutt

Actual

ω = 0.945

I = m(3r/4)^2

= 17.7(3*1.93/4)^2

= 37.08

L = Iω

= 37.08*0.945

= 35.04

Disk

I = mr^2/2

= 93.1(1.93)^2/2

= 173.39

L = Iω

= 173.39*0.945

= 163.85

Total

L = 109.4+ 7.93+ 36.04+ 163.85

= 317.22 kg m^2/s

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