What is the pressure of 0.5 mol nitrogen (N.) gas in a 5.0 L container at 203
1 answer:
Answer:
B) P = 1.7 atm
Explanation:
Number of moles of nitrogen = 0.5 mol
Volume = 5.0 L
Temperature = 203 K
Pressure = ?
Solution:
PV = nRT
P = nRT/V
P = 0.35 mol× 0.0821 atm. L. mol⁻¹. K⁻¹ × 203 K/ 5.0 L
P = 8.333 atm/ 5.0
P = 1.7 atm
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